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Sodium thiosulfate is used to reduce iodine back to iodide before the iodine can complex with the starch to form the characteristic blue-black color. Iodine is generated: 2 I − + S 2 O 2− 8 → I 2 + 2 SO 2− 4. And is then removed: I 2 + 2 S 2 O 2− 3 → 2 I − + S 4 O 2− 6. Once all the thiosulfate is consumed the iodine may form a ...
The iodine content and thus the active chlorine content can be determined with iodometry. [3] The determination of arsenic(V) compounds is the reverse of the standardization of iodine solution with sodium arsenite, where a known and excess amount of iodide is added to the sample: As 2 O 5 + 4 H + + 4 I − ⇌ As 2 O 3 + 2 I 2 + 2 H 2 O
12.69 is the conversion factor from mEq sodium thiosulfate to grams of iodine (the molecular weight of iodine is 126.9 g/mol); W is the weight of the sample in grams. The determination of IV according to Wijs is the official method currently accepted by international standards such as DIN 53241-1:1995-05, AOCS Method Cd 1-25, EN 14111 and ISO ...
Sodium thiosulfate (sodium thiosulphate) is an inorganic compound with the formula Na 2 S 2 O 3 ·(H 2 O) x. Typically it is available as the white or colorless pentahydrate (x = 5), which is a white solid that dissolves well in water. The compound is a reducing agent and a ligand, and these properties underpin its applications. [2]
From the above stoichiometric equations, we can find that: 1 mole of O 2 → 2 moles of MnO(OH) 2 → 2 mole of I 2 → 4 mole of S 2 O 2− 3. Therefore, after determining the number of moles of iodine produced, we can work out the number of moles of oxygen molecules present in the original water sample.
Thiosulfate (IUPAC-recommended spelling; sometimes thiosulphate in British English) is an oxyanion of sulfur with the chemical formula S 2 O 2− 3.Thiosulfate also refers to the compounds containing this anion, which are the salts of thiosulfuric acid, such as sodium thiosulfate Na 2 S 2 O 3 and ammonium thiosulfate (NH 4) 2 S 2 O 3.
Tetrathionate is a product of the oxidation of thiosulfate, S 2 O 2− 3, by iodine, I 2: 2 S 2 O 2− 3 + I 2 → S 4 O 2− 6 + 2I −. The use of bromine instead of iodine is dubious as excess bromine will oxidize the thiosulfate to sulfate.
Sodium tetrathionate is formed by the oxidation of sodium thiosulfate (Na 2 S 2 O 3), e.g. by the action of iodine: [1] 2 Na 2 S 2 O 3 + I 2 → Na 2 S 4 O 6 + 2 NaI. The reaction is signaled by the decoloration of iodine. This reaction is the basis of iodometric titrations. Other methods include the coupling of sodium bisulfite with disulfur ...