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  2. Uniform continuity - Wikipedia

    en.wikipedia.org/wiki/Uniform_continuity

    Linear functions + are the simplest examples of uniformly continuous functions. Any continuous function on the interval [ 0 , 1 ] {\displaystyle [0,1]} is also uniformly continuous, since [ 0 , 1 ] {\displaystyle [0,1]} is a compact set.

  3. Lipschitz continuity - Wikipedia

    en.wikipedia.org/wiki/Lipschitz_continuity

    The function f(x) = √ x defined on [0, 1] is not Lipschitz continuous. This function becomes infinitely steep as x approaches 0 since its derivative becomes infinite. However, it is uniformly continuous, [8] and both Hölder continuous of class C 0, α for α ≤ 1/2 and also absolutely continuous on [0, 1] (both of which imply the former).

  4. Contraction mapping - Wikipedia

    en.wikipedia.org/wiki/Contraction_mapping

    Every contraction mapping is Lipschitz continuous and hence uniformly continuous (for a Lipschitz continuous function, the constant k is no longer necessarily less than 1). A contraction mapping has at most one fixed point.

  5. Hölder condition - Wikipedia

    en.wikipedia.org/wiki/Hölder_condition

    There are examples of uniformly continuous functions that are not α –Hölder continuous for any α. For instance, the function defined on [0, 1/2] by f(0) = 0 and by f(x) = 1/log(x) otherwise is continuous, and therefore uniformly continuous by the Heine-Cantor theorem. It does not satisfy a Hölder condition of any order, however.

  6. Continuous uniform distribution - Wikipedia

    en.wikipedia.org/wiki/Continuous_uniform...

    Any probability density function integrates to , so the probability density function of the continuous uniform distribution is graphically portrayed as a rectangle where ⁠ ⁠ is the base length and ⁠ ⁠ is the height. As the base length increases, the height (the density at any particular value within the distribution boundaries) decreases.

  7. Heine–Cantor theorem - Wikipedia

    en.wikipedia.org/wiki/Heine–Cantor_theorem

    Proof of Heine–Cantor theorem. Suppose that and are two metric spaces with metrics and , respectively.Suppose further that a function : is continuous and is compact. We want to show that is uniformly continuous, that is, for every positive real number > there exists a positive real number > such that for all points , in the function domain, (,) < implies that ((), ()) <.

  8. Continuous function - Wikipedia

    en.wikipedia.org/wiki/Continuous_function

    A function is continuous on a semi-open or a closed interval; if the interval is contained in the domain of the function, the function is continuous at every interior point of the interval, and the value of the function at each endpoint that belongs to the interval is the limit of the values of the function when the variable tends to the ...

  9. Arzelà–Ascoli theorem - Wikipedia

    en.wikipedia.org/wiki/Arzelà–Ascoli_theorem

    The Arzelà–Ascoli theorem is a fundamental result of mathematical analysis giving necessary and sufficient conditions to decide whether every sequence of a given family of real-valued continuous functions defined on a closed and bounded interval has a uniformly convergent subsequence.