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Ken's shocking loss ended a 75-game appearance, winning 74 times, guessing the correct answer 2,700 times and amassing $2.52 million in winnings. Did Ken Jennings compete on Jeopardy! after his ...
As a result, for only the 10th time in 75 games, Jennings did not have an insurmountable lead going into the Final Jeopardy! round. [20] Only Jennings and Zerg, who ended Double Jeopardy! with $10,000, were able to play Final Jeopardy! as third-place contestant David Hankins failed to finish with a positive score after the Double Jeopardy! round.
Rutter, Vered, and Jennings then competed in a three-game cumulative score final match for the top prize. Rutter, who had the highest total in all three of the games, finished with $62,000 and won the $2,000,000 prize. Jennings finished second with $34,599 and collected $500,000, while Vered finished third with $20,600, and took home $250,000. [36]
Rutter entered the tournament having never lost a match against a human, only coming up short in an exhibition match featuring him and Jennings taking on Watson in Jeopardy!: The IBM Challenge in 2011. [11] [7] [8] [12] [4] James Holzhauer: Holzhauer entered the tournament the third-highest-earning Jeopardy! contestant of all time, behind ...
Jennings registered his third win in four games to beat opponents Brad Rutter and James Holzhauer and get the $1 million cash prize. The longest winning streak record holder, with 74 games, had ...
From the time Ken's winning streak began on June 2, 2004 and ended on November 30, 2004, Jeopardy! 's official leaderboard reported that he made a whopping $2,520,700 over the course of 75 games ...
Ken Jennings. Ken Jennings first appeared on Jeopardy! on June 2, 2004, shortly after producers of the show eliminated the five-show cap for contestants. Because the five-game limit was removed, Jennings continued to win and eventually broke the winnings record set by Tom Walsh, who had won $186,900 in 2004.
After four nights of competition, we finally know who the greatest player in "Jeopardy!" history is.