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Sodium peroxide is an inorganic compound with the formula Na 2 O 2.This yellowish solid is the product of sodium ignited in excess oxygen. [3] It is a strong base. This metal peroxide exists in several hydrates and peroxyhydrates including Na 2 O 2 ·2H 2 O 2 ·4H 2 O, Na 2 O 2 ·2H 2 O, Na 2 O 2 ·2H 2 O 2, and Na 2 O 2 ·8H 2 O. [4] The octahydrate, which is simple to prepare, is white, in ...
ClCH 2 CH 2 Cl → CH 2 =CHCl + HCl. The HCl from this cracking process is recycled by oxychlorination in order to reduce the consumption of raw material HCl (or Cl 2, if direct chlorination of ethylene is chosen as main way to produce 1,2-dichloroethane). [3] Iron(III) chloride is produced commercially by oxychlorination (and other methods).
5 NaN 3 + NaNO 3 → 3 Na 2 O + 8 N 2. Burning sodium in air produces a mixture of Na 2 O and sodium peroxide (Na 2 O 2). A third much less known method involves heating sodium metal with iron(III) oxide (rust): 6 Na + Fe 2 O 3 → 3 Na 2 O + 2 Fe. the reaction should be done in an inert atmosphere to avoid the reaction of sodium with the air ...
Cl 2 + H 2 → 2 HCl. As the reaction is exothermic, the installation is called an HCl oven or HCl burner. The resulting hydrogen chloride gas is absorbed in deionized water, resulting in chemically pure hydrochloric acid. This reaction can give a very pure product, e.g. for use in the food industry. The reaction can also be triggered by blue ...
2 FeCl 3 + 3 H 2 S → Fe 2 S 3 + 6 HCl. The stoichiometric masses for this reaction are: 324.41 g FeCl 3, 102.25 g H 2 S, 207.89 g Fe 2 S 3, 218.77 g HCl. Suppose 90.0 g of FeCl 3 reacts with 52.0 g of H 2 S. To find the limiting reagent and the mass of HCl produced by the reaction, we change the above amounts by a factor of 90/324.41 and ...
Hypochlorous acid is an inorganic compound with the chemical formula Cl O H, also written as HClO, HOCl, or ClHO. [2] [3] Its structure is H−O−Cl.It is an acid that forms when chlorine dissolves in water, and itself partially dissociates, forming a hypochlorite anion, ClO −.
For example, hydrochloric acid, HCl, is a strong acid. HCl(aq) → H + (aq) + Cl − (aq) A strong base is one that is fully dissociated in aqueous solution. For example, sodium hydroxide, NaOH, is a strong base. NaOH(aq) → Na + (aq) + OH − (aq) Therefore, when a strong acid reacts with a strong base the neutralization reaction can be ...
2 NaCl + 2H 2 SO 4 + MnO 2 → Na 2 SO 4 + MnSO 4 + 2 H 2 O + Cl 2. Using this process, chemist Carl Wilhelm Scheele was the first to isolate chlorine in a laboratory. The manganese can be recovered by the Weldon process. [11]
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