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  2. Clausius–Clapeyron relation - Wikipedia

    en.wikipedia.org/wiki/ClausiusClapeyron_relation

    Substituting into the Clapeyron equation =, we can obtain the Clausius–Clapeyron equation [8]: 509 = for low temperatures and pressures, [8]: 509 where is the specific latent heat of the substance. Instead of the specific, corresponding molar values (i.e. L {\\displaystyle L} in kJ/mol and R = 8.31 J/(mol⋅K)) may also be used.

  3. Ehrenfest equations - Wikipedia

    en.wikipedia.org/wiki/Ehrenfest_equations

    Ehrenfest equations (named after Paul Ehrenfest) are equations which describe changes in specific heat capacity and derivatives of specific volume in second-order phase transitions. The Clausius–Clapeyron relation does not make sense for second-order phase transitions, [ 1 ] as both specific entropy and specific volume do not change in second ...

  4. Clausius theorem - Wikipedia

    en.wikipedia.org/wiki/Clausius_theorem

    The Clausius theorem is a mathematical representation of the second law of thermodynamics. It was developed by Rudolf Clausius who intended to explain the relationship between the heat flow in a system and the entropy of the system and its surroundings. Clausius developed this in his efforts to explain entropy and define it quantitatively.

  5. Talk:Clausius–Clapeyron relation - Wikipedia

    en.wikipedia.org/wiki/Talk:ClausiusClapeyron...

    The textbook Introduction to Chemical Engineering Thermodynamics (6th ed.) by Smith, Van Ness, and Abbott makes a distinction between the exact equation (which it calls the Clapeyron equation; it is equivalent to the one discussed in this article) and the approximate equation (which it calls the Clausius/Clapeyron equation; it seems to be ...

  6. Methanol (data page) - Wikipedia

    en.wikipedia.org/wiki/Methanol_(data_page)

    Here is a similar formula from the 67th edition of the CRC handbook. Note that the form of this formula as given is a fit to the Clausius–Clapeyron equation, which is a good theoretical starting point for calculating saturation vapor pressures: log 10 (P) = −(0.05223)a/T + b, where P is in mmHg, T is in kelvins, a = 38324, and b = 8.8017.

  7. Reflections on the Motive Power of Fire - Wikipedia

    en.wikipedia.org/wiki/Reflections_on_the_Motive...

    The book is considered the founding work of thermodynamics. [2]: viii It contains the preliminary outline of the second law of thermodynamics.Carnot stated that motive power is due to the fall of caloric (chute de calorique) from a hot to a cold body, which he analogized to the work done by a water wheel due to a waterfall (chute d'eau).

  8. Rudolf Clausius - Wikipedia

    en.wikipedia.org/wiki/Rudolf_Clausius

    He used the now abandoned unit 'Clausius' (symbol: Cl) for entropy. [17] 1 Clausius (Cl) = 1 calorie/degree Celsius (cal/°C) = 4.1868 joules per kelvin (J/K) The landmark 1865 paper in which he introduced the concept of entropy ends with the following summary of the first and second laws of thermodynamics: [4] The energy of the universe is ...

  9. Mason equation - Wikipedia

    en.wikipedia.org/wiki/Mason_Equation

    In Mason's formulation the changes in temperature across the boundary layer can be related to the changes in saturated vapour pressure by the Clausius–Clapeyron relation; the two energy transport terms must be nearly equal but opposite in sign and so this sets the interface temperature of the drop. The resulting expression for the growth rate ...