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Since no prime number divides 1, p cannot be in the list. This means that at least one more prime number exists that is not in the list. This proves that for every finite list of prime numbers there is a prime number not in the list. [4] In the original work, Euclid denoted the arbitrary finite set of prime numbers as A, B, Γ. [5]
The intersection of two (and hence finitely many) open sets is open: let U 1 and U 2 be open sets and let x ∈ U 1 ∩ U 2 (with numbers a 1 and a 2 establishing membership). Set a to be the least common multiple of a 1 and a 2. Then S(a, x) ⊆ S(a i, x) ⊆ U i. This topology has two notable properties:
In 1737, Euler related the study of prime numbers to what is known now as the Riemann zeta function: he showed that the value () reduces to a ratio of two infinite products, Π p / Π (p–1), for all primes p, and that the ratio is infinite. [1] [2] In 1775, Euler stated the theorem for the cases of a + nd, where a = 1. [3]
If an AP-k does not begin with the prime k, then the common difference is a multiple of the primorial k# = 2·3·5·...·j, where j is the largest prime ≤ k. Proof: Let the AP-k be a·n + b for k consecutive values of n. If a prime p does not divide a, then modular arithmetic says that p will divide every p'th term of the arithmetic ...
If n is prime, there is nothing more to prove. Otherwise, there are integers a and b, where n = a b, and 1 < a ≤ b < n. By the induction hypothesis, a = p 1 p 2 ⋅⋅⋅ p j and b = q 1 q 2 ⋅⋅⋅ q k are products of primes. But then n = a b = p 1 p 2 ⋅⋅⋅ p j q 1 q 2 ⋅⋅⋅ q k is a product of primes.
Every Euclid number is congruent to 3 modulo 4 since the primorial of which it is composed is twice the product of only odd primes and thus congruent to 2 modulo 4. This property implies that no Euclid number can be a square. For all n ≥ 3 the last digit of E n is 1, since E n − 1 is divisible by 2 and 5.