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The Tybee Island mid-air collision was an incident on February 5, 1958, in which the United States Air Force lost a 7,600-pound (3,400 kg) Mark 15 nuclear bomb in the waters off Tybee Island near Savannah, Georgia, United States.
It is the location of a hydrogen bomb lost by a B-47 Stratojet bomber in 1958. This lost hydrogen bomb is also known as the Tybee Bomb.On the night of February 5, 1958, a B-47 Stratojet bomber carrying a hydrogen bomb on a night training flight off the Georgia coast collided with an F-86 Saberjet fighter at 36,000 feet.
They did not provide details, but the site that initially shared the fake Georgia video was behind an Oct. 30 post on X falsely claiming Harris and her husband Doug Emhoff had tipped off now ...
The 1964 Savage Mountain B-52 crash was a U.S. military nuclear accident in which a Cold War bomber's vertical stabilizer broke off in winter storm turbulence. [3] The two nuclear bombs being ferried were found "relatively intact in the middle of the wreckage", according to a later U.S. Department of Defense summary, [4] and after Fort Meade's 28th Ordnance Detachment secured them, [5] the ...
Unit 3 first went online last July. At a cost of $35 million (more than $17 million higher than projected), i was the first nuclear reactor built from the ground up in the U.S. in over 30 years ...
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The airstrike was carried out using the largest non-nuclear bomb in the United States' arsenal, the GBU-43/B Massive Ordnance Air Blast (MOAB), with the goal of destroying tunnel complexes used by the Islamic State – Khorasan Province (IS-KP). [5] [6] [7] The bomb was dropped from the rear cargo door of a United States Air Force Lockheed MC-130.