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The primary has an inductance of 38 uH and couples to the secondaries with a turns ratio of 2:1 and 2:1.1. The 2:1 coupling means that the secondary inductance is \$(1:2)^2\$ x 38 uH = 9.5 uH.
The formula is: Where: λ = Wavelength k = 20 for a slit or 40 for a round hole L = Longest dimension of the aperture If there is more than one hole, we subtract from the original formula: the total number of holes within half a wavelength. Likewise, Analyse on shielding effectiveness of board level shielding with apertures says: Where: n ...
The short answer is yes--we can calculate the baud rate or communication speed of RS232 communication from the X output signal. According to the scope, the bit width is 100us. Inverting gives a baud rate of 10K. ~1 bit / 100us = 10,000 bit/s = 10K baud. Here are traces of the "5" character being sent at 115K baud and 1200 baud respectively.
Sometimes a pullup is used to hold a signal that is otherwise undriven. In this case, the load current will be the leakage current of any connected devices. (Typically micro or nano amperes). It is relatively easy to calculate the resistance needed with this information.
Then you turn the excitation off (it would be a current source for an impedance determination) and you calculate the various time constants in this mode. For the numerator, you short the current source (the nulled response across the current source makes it a short circuit for the zero determination) and you determine the new time constants in ...
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I am trying to calculate parameters such as base current, collector current, Vce using hFE (beta). The base signal is a 5V pulse. The formulas that I followed: Ib = (Vcc-Vbe) / ( Rb + (beta+1)x Re. Here Vcc is 5 V pulse. Vcc = Vce + Ic ( Rc + Re) I assumed that Ic is almost same as Ie and Vcc is 20 V here. No matter what beta values I use, I ...
Suppose you have a beam light inside a room. The power consumed by the beam light minus the lighting power pass out of this room is the heat dissipated in this room. Another example thst suppose you have a production machine inside a factory and you need to calculate the heat dissipation from this machine to calculate the cooling load.
Obviously, for high-pass filters for example, you calculate with the value for \$\omega\to \infty\$ as opposed to the DC value (always the maximum of the amplitude response, relative to which there is a 3dB decrease in amplitude at the cutoff frequency.)
Power isn't "across" something. Power is the voltage across something times the current going through it. Since the small amount of current going into the base is irrelevant in power dissipation, calculate the C-E voltage and the collector current. The power dissipated by the transistor will be the product of those two.