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pound per square foot: psf ≡ 1 lbf/ft 2: ≈ 47.880 26 Pa [33] pound per square inch: psi ≡ 1 lbf/in 2: ≈ 6.894 757 × 10 3 Pa [33] poundal per square foot: pdl/sq ft ≡ 1 pdl/sq ft ≈ 1.488 164 Pa [33] short ton per square foot: ≡ 1 short ton × g 0 / 1 sq ft ≈ 9.576 0518 × 10 4 Pa: torr: torr ≡ 101 325 ⁄ 760 Pa ≈ 133.3224 ...
In the cases where non-SI units are used, the numerical calculation of a formula can be done by first working out the factor, and then plug in the numerical values of the given/known quantities. For example, in the study of Bose–Einstein condensate , [ 6 ] atomic mass m is usually given in daltons , instead of kilograms , and chemical ...
Comparison of 1 square foot with some Imperial and metric units of area. The square foot (pl. square feet; abbreviated sq ft, sf, or ft 2; also denoted by ' 2 and ⏍) is an imperial unit and U.S. customary unit (non-SI, non-metric) of area, used mainly in the United States, Canada, the United Kingdom, Bangladesh, India, Nepal, Pakistan, Ghana, Liberia, Malaysia, Myanmar, Singapore and Hong Kong.
Comparison of 1 square yard with some Imperial and metric units of area The square yard ( Northern India : gaj , Pakistan : gaz ) is an imperial unit and U.S. customary unit of area . It is in widespread use in most of the English -speaking world, particularly the United States, United Kingdom, Canada, Pakistan and India.
The square root appearing above can be eliminated for such applications as ordering locations by distance in a database query. On the other hand, some methods for computing nearest neighbors, such as the vantage-point tree , require that the distance metric obey the triangle inequality , in which case the square root must be retained.
The foot per second squared (plural feet per second squared) is a unit of acceleration. [1] It expresses change in velocity expressed in units of feet per second (ft/s) divided by time in seconds (s) (or the distance in feet (ft) traveled or displaced, divided by the time in seconds (s) squared).
Using this term, one can calculate many things in the same way as for a round tube. When the cross-section is uniform along the tube or channel length, it is defined as [1] [2] =, where A is the cross-sectional area of the flow, P is the wetted perimeter of the cross-section.
To complete the square, form a squared binomial on the left-hand side of a quadratic equation, from which the solution can be found by taking the square root of both sides. The standard way to derive the quadratic formula is to apply the method of completing the square to the generic quadratic equation a x 2 + b x + c = 0 {\displaystyle ...