Search results
Results From The WOW.Com Content Network
An F-score is a combination of the precision and the recall, providing a single score. There is a one-parameter family of statistics, with parameter β, which determines the relative weights of precision and recall. The traditional or balanced F-score is the harmonic mean of precision and recall:
A non-degenerate random variable Z is α-stable for some 0 < α ≤ 2 if and only if there is an independent, identically distributed sequence of random variables X 1, X 2, X 3, ... and constants a n > 0, b n ∈ ℝ with a n (X 1 + ... + X n) − b n → Z.
A 95% confidence level does not mean that 95% of the sample data lie within the confidence interval. A 95% confidence level does not mean that there is a 95% probability of the parameter estimate from a repeat of the experiment falling within the confidence interval computed from a given experiment. [25]
Back in 2012, when Zuckerberg was #40 on the list with an estimated $15.6 billion net worth, he refinanced his home in Palo Alto, California, with a 30-year adjustable rate mortgage at 1.05% ...
The Student's t-distribution is approximately normal with mean 0 and variance 1 when is large. Whether these approximations are sufficiently accurate depends on the purpose for which they are needed, and the rate of convergence to the normal distribution.
The cells in the human body are not outnumbered 10 to 1 by microorganisms. The 10 to 1 ratio was an estimate made in 1972; current estimates put the ratio at either 3 to 1 or 1.3 to 1. [300] The total length of capillaries in the human body is not 100,000 km.
Combs and his legal team have full confidence in the facts and the integrity of the judicial process. ... The 10 carry-on essentials that make for a first-class experience, according to pilots ...
Under these conditions the 95% VaR for holding either of the bonds is 0 since the probability of default is less than 5%. However if we held a portfolio that consisted of 50% of each bond by value then the 95% VaR is 35% (= 0.5*0.7 + 0.5*0) since the probability of at least one of the bonds defaulting is 7.84% (= 1 - 0.96*0.96) which exceeds 5%.