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  2. AM–GM inequality - Wikipedia

    en.wikipedia.org/wiki/AM–GM_inequality

    Proof without words of the AM–GM inequality: PR is the diameter of a circle centered on O; its radius AO is the arithmetic mean of a and b. Using the geometric mean theorem, triangle PGR's altitude GQ is the geometric mean. For any ratio a:b, AO ≥ GQ. Visual proof that (x + y) 2 ≥ 4xy. Taking square roots and dividing by two gives the AM ...

  3. QM-AM-GM-HM inequalities - Wikipedia

    en.wikipedia.org/wiki/QM-AM-GM-HM_Inequalities

    There are three inequalities between means to prove. There are various methods to prove the inequalities, including mathematical induction, the Cauchy–Schwarz inequality, Lagrange multipliers, and Jensen's inequality. For several proofs that GM ≤ AM, see Inequality of arithmetic and geometric means.

  4. File:AM GM inequality visual proof.svg - Wikipedia

    en.wikipedia.org/wiki/File:AM_GM_inequality...

    Proof without words of the inequality of arithmetic and geometric means, drawn by CMG Lee. PR is a diameter of a circle centred on O; its radius AO is the arithmetic mean of a and b . Using the geometric mean theorem, right triangle PGR can be split into two similar triangles PQG and GQR; GQ / a = b / GQ, hence GQ = √( ab ), the geometric mean.

  5. Generalized mean - Wikipedia

    en.wikipedia.org/wiki/Generalized_mean

    The proof follows from Jensen's inequality, making use of the fact the logarithm is concave: ⁡ = = = ⁡ ⁡ =. By applying the exponential function to both sides and observing that as a strictly increasing function it preserves the sign of the inequality, we get ∏ i = 1 n x i w i ≤ ∑ i = 1 n w i x i . {\displaystyle \prod _{i=1}^{n}x ...

  6. Bernoulli's inequality - Wikipedia

    en.wikipedia.org/wiki/Bernoulli's_inequality

    Bernoulli's inequality can be proved for case 2, in which is a non-negative integer and , using mathematical induction in the following form: we prove the inequality for {,}, from validity for some r we deduce validity for +.

  7. Nesbitt's inequality - Wikipedia

    en.wikipedia.org/wiki/Nesbitt's_inequality

    1.1 First proof: AM-HM inequality. 1.2 Second proof: Rearrangement. 1.3 Third proof: Sum of Squares. 1.4 Fourth proof: Cauchy–Schwarz. ... Fifth proof: AM-GM

  8. Pythagorean means - Wikipedia

    en.wikipedia.org/wiki/Pythagorean_means

    The proof follows from the arithmetic–geometric mean inequality, , and reciprocal duality (and are also reciprocal dual to each other). The study of the Pythagorean means is closely related to the study of majorization and Schur-convex functions. The harmonic and geometric means are concave symmetric functions of their arguments, and hence ...

  9. Template:AM GM inequality visual proof.svg - Wikipedia

    en.wikipedia.org/wiki/Template:AM_GM_inequality...

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