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  2. 1. You could use a Common Table Expression to create the SUM first, join it to the table, and then use the WHEN to to get the value from the CTE or the original table as necessary. SELECT Id, (cnt / SUM(AreaId)) FROM dbo.MyTable GROUP BY Id.

  3. I can sum up the amount of payments by executing 2 SQL statements as shown below. In this case, the user won't even notice the speed difference when executing 2 sql statements or just 1, however, I don't like my way, I just want 1 sql statement.

  4. Sum function in Case statement - Stack Overflow

    stackoverflow.com/questions/47409467

    The sub-query will contain the SUM(C_Amount) in each row (since you are using the analytic function with OVER (PARTITION BY item)) and then summing these in the outer query you are effectively doing SELECT COUNT(1) * SUM(C_Amount) AS S_C_Amount FROM table A GROUP BY item which is not the output the OP wants.

  5. SQL GROUP BY with a SUM CASE statement - Stack Overflow

    stackoverflow.com/questions/25288847

    SQL GROUP BY CASE statement with aggregate function. but I've tried doing: with T as (select col1 , SUM(CASE WHEN col2 = 1 THEN col3 ELSE 0 END) AS Totale from tabella group by col1, col2) select col1, Totale from T group by col1, Totale but I'm getting. col1 | Totale ----- 1 0 1 70 2 0 2 90

  6. sql - Mysql SUM with case statement - Stack Overflow

    stackoverflow.com/questions/6878090

    Yes it does! A shorter and cleaner query (IMHO) would be to use IF statement: SELECT SUM(IF(cumulative = 1, `percent`, 0)) FROM phppos_items_taxes; answered Jul 29, 2011 at 19:34. Shef. 45.5k 15 81 90. 4. Shorter, yes, but the IF () syntax is not ANSI SQL. Using CASE increases the chance of being portable, for what that's worth.

  7. SQL GROUP BY CASE statement with aggregate function

    stackoverflow.com/questions/1208854

    Select Sum(Case When col1 > col2 Then col3*col4 Else 0 End) as SumSomeProduct. From ... Group By Case When col1 > col2 Then col3*col4 Else 0 End. Finally, if you want to group By the actual aggregate. Select SumSomeProduct, Count(*), <other aggregate functions>. From (Select <other columns you are grouping By>,

  8. postgresql - SQL SELECT CASE WHEN SUM - Stack Overflow

    stackoverflow.com/questions/61899913

    0. Group By 1 --> will Group by the first column, that has aggregate function sum() That is not allowed, So the query should be as follows. Select Case when duration between 0 and 5 then '0-5'. when duration between 0 and 5 then '5-10'. Else '10+'.

  9. 2. Try using COUNT with DISTINCT on a forced 1-value CASE statement. Note that this will only yield values 1 or 0, since counting distinct result_code with a particular value will always return 1 if any exists or 0 if it doesn't. select. COUNT(DISTINCT(case when result_code = 'PZ01' then result_code end)) as Hub_Box_Activated.

  10. I'm looking to see if there is a better approach to the query below. What I'm trying to do is create a summary report, compiling stats by date. SELECT CAST(Detail.ReceiptDate AS DATE) AS 'DATE'. , SUM(CASE WHEN Detail.Type = 'TotalMailed' THEN 1 ELSE 0 END) AS 'TOTALMAILED'. , SUM(CASE WHEN Detail.Type = 'TotalReturnMail' THEN 1 ELSE 0 END) AS ...

  11. This works, but now I need a sum because there are multiple rows. SELECT. SUM(. CASE schuleArtID. WHEN 1 THEN SUM(schuleSummeSchueler) / 8. WHEN 2 THEN SUM(schuleSummeSchueler) / 6 * 0.8. WHEN 3 THEN SUM(schuleSummeSchueler) / 6 * 0.8. WHEN 4 THEN SUM(schuleSummeSchueler) / 5 * 0.8.