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[5] A trick is to count up valence electrons, then count up the number of electrons needed to complete the octet rule (or with hydrogen just 2 electrons), then take the difference of these two numbers. The answer is the number of electrons that make up the bonds. The rest of the electrons just go to fill all the other atoms' octets.
Tin(II) bromide can act as a Lewis acid forming adducts with donor molecules e.g. trimethylamine where it forms NMe 3 ·SnBr 2 and 2NMe 3 ·SnBr 2 [11] It can also act as both donor and acceptor in, for example, the complex F 3 B·SnBr 2 ·NMe 3 where it is a donor to boron trifluoride and an acceptor to trimethylamine.
In solutions containing the fluoride ion, F −, it forms the fluoride complexes SnF 3 −, Sn 2 F 5 −, and SnF 2 (OH 2). [26] Crystallization from an aqueous solution containing NaF produces compounds containing polynuclear anions, e.g. NaSn 2 F 5 or Na 4 Sn 3 F 10 depending on the reaction conditions, rather than NaSnF 3 . [ 20 ]
[5] [6] SnC 2 O 4 ·2H 2 O → SnO + CO 2 + CO + 2 H 2 O. Tin(II) oxide burns in air with a dim green flame to form SnO 2. [4] 2 SnO + O 2 → 2 SnO 2. When heated in an inert atmosphere initially disproportionation occurs giving Sn metal and Sn 3 O 4 which further reacts to give SnO 2 and Sn metal. [4] 4SnO → Sn 3 O 4 + Sn Sn 3 O 4 → 2SnO ...
To obtain tin(II) acetate, tin(II) oxide is dissolved in glacial acetic acid and refluxed to obtain yellow Sn(CH 3 COO) 2 ·2CH 3 COOH when cooled. The acetic acid can be removed by heating under reduced pressure, and the white Sn(CH 3 COO) 2 crystals can be obtained by sublimation.
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The range of organic reactions also include SN2 reactions: [12] With E = −9.15 for the S-methyldibenzothiophenium ion, typical nucleophile values N (s) are 15.63 (0.64) for piperidine, 10.49 (0.68) for methoxide, and 5.20 (0.89) for water. In short, nucleophilicities towards sp 2 or sp 3 centers follow the same pattern.