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This clock reaction uses sodium, potassium or ammonium persulfate to oxidize iodide ions to iodine. Sodium thiosulfate is used to reduce iodine back to iodide before the iodine can complex with the starch to form the characteristic blue-black color. Iodine is generated: 2 I − + S 2 O 2− 8 → I 2 + 2 SO 2− 4. And is then removed:
The color change can be used to detect moisture or perspiration, as in the Minor test or starch–iodine test. A starch agar plate filled up with iodine. A holo is present around B. subtilis. Starch is also useful in detecting the enzyme amylase, which breaks down starch into sugars.
I 2 dissolves in the iodide-containing solution to give triiodide ions (I 3 −), which have a dark brown color. The triiodide ion solution is then titrated against standard thiosulfate solution to give iodide again using starch indicator: I − 3 + 2 e − ⇌ 3 I − (E 0 = +0.54 V) Together with reduction potential of thiosulfate: [1]
Starch is optionally added as an indicator to show the abrupt increase in iodide ion concentration as a sudden change from amber (free iodine) to dark blue (the "iodine-starch complex", which requires both iodine and iodide.) [7] Recently it has been shown, however, that the starch is not only an indicator for iodine in the reaction. [8]
Potassium iodide is a component in the electrolyte of dye sensitised solar cells (DSSC) along with iodine. Potassium iodide finds its most important applications in organic synthesis mainly in the preparation of aryl iodides in the Sandmeyer reaction, starting from aryl amines. Aryl iodides are in turn used to attach aryl groups to other ...
The solution is then treated with various reagents to test for reactions characteristic of certain ions, which may cause color change, precipitation and other visible changes. [ 1 ] [ 2 ] Qualitative inorganic analysis is that branch or method of analytical chemistry which seeks to establish the elemental composition of inorganic compounds ...
A solution of iodine I 2 is yellow/brown in color. When this is added to a solution to be tested, however, any chemical group (usually in this test −C=C− double bonds) that react with iodine effectively reduce the strength, or magnitude of the color (by taking I 2 out of solution). Thus the amount of iodine required to make a solution ...
The black precipitate of bismuth iodide is formed from the reaction of bismuth ion and potassium iodide. Bi 3+ + 3 KI → BiI 3 + 3 K + Then, the reaction between bismuth ion and excess potassium iodide will produce a soluble complex of potassium tetraiodobismuthate which has an orange color. BiI 3 + KI → K(BiI 4)