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The function in example 1, a removable discontinuity. Consider the piecewise function = {< = >. The point = is a removable discontinuity.For this kind of discontinuity: The one-sided limit from the negative direction: = and the one-sided limit from the positive direction: + = + at both exist, are finite, and are equal to = = +.
Let be a real-valued monotone function defined on an interval. Then the set of discontinuities of the first kind is at most countable.. One can prove [5] [3] that all points of discontinuity of a monotone real-valued function defined on an interval are jump discontinuities and hence, by our definition, of the first kind.
For example, the double angle ... The Chebyshev polynomials of the second kind are defined by the recurrence relation: = () ... At a discontinuity, the series will ...
For example, if = and time is the ... is the Hankel function of the second kind, and () is the spherical Hankel ... One can ensure proper discontinuity in the first ...
A Kleinian group is said to be of finite type if its region of discontinuity has a finite number of orbits of components under the group action, and the quotient of each component by its stabilizer is a compact Riemann surface with finitely many points removed, and the covering is ramified at finitely many points.
Then, the point x 0 = 1 is a jump discontinuity. In this case, a single limit does not exist because the one-sided limits, L − and L +, exist and are finite, but are not equal: since, L − ≠ L +, the limit L does not exist. Then, x 0 is called a jump discontinuity, step discontinuity, or discontinuity of the first kind.
The Dirichlet function is not Riemann-integrable on any segment of despite being bounded because the set of its discontinuity points is not negligible (for the Lebesgue measure). The Dirichlet function provides a counterexample showing that the monotone convergence theorem is not true in the context of the Riemann integral.
An infinite discontinuity is the special case when either the left hand or right hand limit does not exist, specifically because it is infinite, and the other limit is either also infinite, or is some well defined finite number. In other words, the function has an infinite discontinuity when its graph has a vertical asymptote.