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This value must be less than or equal to precision. A scale of 0 produces integral values, with no fractional part. Since you don't want any number to the right, you can try this. df.withColumn("s", 'value.cast("Decimal(10,0)")) If you want to keep 4 decimal digits, you can just change it to.
10. The scientific notation can be converted to a floating point number with float. In [1]: float("8.99284722486562e-02") Out [1]: 0.0899284722486562. The float can be rounded with format and then float can be used on the string to return the final rounded float.
Second thing, bash doesn't know scientific notation (even for integers). First thing you can try, if you're absolutely positively sure that all your numbers are integers: convert them to decimal notation: printf will happily do that for you:
For eg. I have a recursive function where last answer coming like 4.12345678e10, if I convert this to standard notation it would result like this 41234567800 where last two digits 00 are not actually 00. So it would be better if there is a way to prevent conversion to scientific notation or any other hack. –
and this is formed using this line in my code: list1.append(np.array(regr.predict(data),dtype = np.float)) Now I want to convert elements in list1 from scientific format to decimal format. I looked around for some solution and found out that print format(0.00001357, 'f') converts numbers from scientific format to decimal format but how do I use ...
I know how to do string formatting in python but I'm at a loss when it comes to applying it here. df1.groupby('dept')['data1'].sum() dept. value1 1.192433e+08. value2 1.293066e+08. value3 1.077142e+08. This suppresses the scientific notation if I convert to string but now I'm just wondering how to string format and add decimals.
I would like to have consistent output for a particular R script. In this case, I would like all numeric output to be in scientific notation with exactly two decimal places. Examples: 0.05 --> 5.00e-02. 0.05671 --> 5.67e-02. 0.000000027 --> 2.70e-08. I tried using the following options:
To convert a Decimal to scientific notation without needing to specify the precision in the format string, and without including trailing zeros, I'm currently using def sci_str(dec): return ('{:.' + str(len(dec.normalize().as_tuple().digits) - 1) + 'E}').format(dec) print( sci_str( Decimal('123.456000') ) ) # 1.23456E+2
Since decimal separator ("." in your string) can vary from culture to culture it's safier to use InvariantCulture. Do not forget to allow this decimal separator (NumberStyles.Float) decimal h = Decimal.Parse( "2.09550901805872E-05", NumberStyles.Float | NumberStyles.AllowExponent, CultureInfo.InvariantCulture);
I'm assuming this value has been imported to a column. For this to work, 1) the new column was created with the info above, 2) the current column was updated to a blank, 3) that column was altered as the proper varchar value, 4) the original then updated with the updated values from the query above, 5) the new column dropped, and 6) the transaction committed.