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Use the guidelines below to determine how many pounds of potatoes per person you need for dinner. Potatoes can weigh anywhere from 1/10 pound to 1/2 pound, depending on their size. Related: How ...
The imperial gallon was originally defined as 10 pounds (4.5359 kg) of water in 1824, and refined as exactly 4.54609 litres in 1985. Traditionally, when describing volumes, recipes commonly give measurements in the following units: Tumbler (10 fluid ounces; [29] [30] named after a typical drinking glass)
A sweet potato casserole recipe might call for three pounds, or about 48 ounces, of sweet potatoes. By Burgess’s estimation, that should equate to 9 to 12 servings. By Burgess’s estimation ...
Follow our simple formula.
≈64.80 mg: 1 ⁄ 7000 of a pound Dram/drachm (dr) ≈1.772 g: sixteenth of an ounce (possibly originated as the weight of silver in Ancient Greek coin drachma) Ounce (oz) ≈28.35 g: 1 oz = 16 dr = 437.5 grains Pound (lb) ≈453.6 g: 1 lb = 16 oz = 7000 grains ('lb' is an abbreviation for the Ancient Roman unit libra) Stone (st) 6.35 kg
An imperial fluid ounce is defined in British law as exactly 28.4130625 millilitres, [15] while a US customary fluid ounce is exactly 29.5735295625 mL, [16] and a US food labelling fluid ounce is 30 mL. [17] The fluid ounce is sometimes referred to simply as an "ounce" in contexts where its use is implicit, such as bartending.
So if you're making dinner for two, that's 1 pound of potatoes. But if you're cooking for a crowd, or say six people, that's three pounds of potatoes. Here's a breakdown of what you'll need per ...
An imperial fluid ounce is 1 ⁄ 20 of an imperial pint, 1 ⁄ 160 of an imperial gallon or exactly 28.4130625 mL. A US customary fluid ounce is 1 ⁄ 16 of a US liquid pint and 1 ⁄ 128 of a US liquid gallon or exactly 29.5735295625 mL, making it about 4.08% larger than the imperial fluid ounce. A US food labeling fluid ounce is exactly 30 mL.