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The age term is (140 – age). This means that a 20-year-old person (140 – 20 = 120) will have twice the creatinine clearance as an 80-year-old (140 – 80 = 60) for the same level of serum creatinine. The C-G equation assumes that a woman will have a 15% lower creatinine clearance than a man at the same level of serum creatinine.
A better estimate of kidney function is given by calculating the estimated glomerular filtration rate (eGFR). eGFR can be calculated without a 24-hour urine collection, using serum creatinine concentration and some or all of the following variables: sex, age, and weight, as suggested by the American Diabetes Association. [19]
The above formula only applies for GFR calculation when it is equal to the clearance rate. The normal range of GFR, adjusted for body surface area , is 100–130 average 125 (mL/min)/(1.73 m 2 ) in men and 90–120 (mL/min)/(1.73 m 2 ) in women younger than the age of 40.
Fractional excretion of other substances can be measured to determine kidney clearance including urea, uric acid, and lithium. These can be used in patients undergoing diuretic therapy, since diuretics induce a natriuresis. Thus, the urinary sodium concentration and FE Na may be higher in patients receiving diuretics in spite of prerenal ...
The renal clearance ratio or fractional excretion is a relative measure of the speed at which a constituent of urine passes through the kidneys. [ 1 ] [ 2 ] It is defined by following equation: c l e a r a n c e r a t i o o f X = C x C i n {\displaystyle clearance\ ratio\ of\ X={\frac {C_{x}}{C_{in}}}}
A simple means of estimating renal function is to measure pH, blood urea nitrogen, creatinine, and basic electrolytes (including sodium, potassium, chloride, and bicarbonate). As the kidney is the most important organ in controlling these values, any derangement in these values could suggest renal impairment.
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Kt/V and standardized Kt/V are not the same. Kt/V is a ratio of the pre- and post-dialysis urea concentrations. Standardized Kt/V is an equivalent clearance defined by the initial urea concentration (compare equation 8 and equation 10).