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Original and simplified example circuit. While there are many ways to minimize a circuit, this is an example that minimizes (or simplifies) a Boolean function. The Boolean function carried out by the circuit is directly related to the algebraic expression from which the function is implemented. [7]
An AOI21 logic gate in CMOS using a complex gate (left) and standard gates (right) AND-OR-invert (AOI) and OAI gates can be readily implemented in CMOS circuitry. AOI gates are particularly advantaged in that the total number of transistors (or gates) is less than if the AND, NOT, and OR functions were implemented separately.
For example, an 8:1 multiplexer can be made with two 4:1 and one 2:1 multiplexers. The two 4:1 multiplexer outputs are fed into the 2:1 with the selector pins on the 4:1's put in parallel giving a total number of selector inputs to 3, which is equivalent to an 8:1.
In Boolean algebra, any Boolean function can be expressed in the canonical disjunctive normal form , [1] minterm canonical form, or Sum of Products (SoP or SOP) as a disjunction (OR) of minterms. The De Morgan dual is the canonical conjunctive normal form ( CCNF ), maxterm canonical form , or Product of Sums ( PoS or POS ) which is a ...
The POS expression gives a complement of the function (if F is the function so its complement will be F'). [10] Karnaugh maps can also be used to simplify logic expressions in software design. Boolean conditions, as used for example in conditional statements, can get very complicated, which makes the code difficult to read and to maintain. Once ...
The very fastest shifters are implemented as full crossbars, in a manner similar to the 4-bit shifter depicted above, only larger. These incur the least delay, with the output always a single gate delay behind the input to be shifted (after allowing the small time needed for the shift count decoder to settle; this penalty, however, is only incurred when the shift count changes).
The carry-select adder generally consists of ripple-carry adders and a multiplexer.Adding two n-bit numbers with a carry-select adder is done with two adders (therefore two ripple-carry adders), in order to perform the calculation twice, one time with the assumption of the carry-in being zero and the other assuming it will be one.
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