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Cycles of the unit digit of multiples of integers ending in 1, 3, 7 and 9 (upper row), and 2, 4, 6 and 8 (lower row) on a telephone keypad. Figure 1 is used for multiples of 1, 3, 7, and 9. Figure 2 is used for the multiples of 2, 4, 6, and 8. These patterns can be used to memorize the multiples of any number from 0 to 10, except 5.
In mathematics, a multiple is the product of any quantity and an integer. [1] In other words, for the quantities a and b , it can be said that b is a multiple of a if b = na for some integer n , which is called the multiplier .
The units from 1 to 9 are assigned to the first nine letters of the old Ionic alphabet from alpha to theta. Instead of reusing these numbers to form multiples of the higher powers of ten, however, each multiple of ten from 10 to 90 was assigned its own separate letter from the next nine letters of the Ionic alphabet from iota to koppa.
a happy number [6] and a self number in base 10. [7] with an aliquot sum of 46; itself a semiprime, within an aliquot sequence of seven members (86,46,26,16,15,9,4,3,1,0) in the Prime 3-aliquot tree. It appears in the Padovan sequence, preceded by the terms 37, 49, 65 (it is the sum of the first two of these). [8]
The system of ancient Egyptian numerals was used in Ancient Egypt from around 3000 BC [1] until the early first millennium AD. It was a system of numeration based on multiples of ten, often rounded off to the higher power, written in hieroglyphs. The Egyptians had no concept of a positional notation such as the decimal system. [2]
Demonstration, with Cuisenaire rods, of the divisors of the composite number 10 Composite numbers can be arranged into rectangles but prime numbers cannot. A composite number is a positive integer that can be formed by multiplying two smaller positive integers. Accordingly it is a positive integer that has at least one divisor other than 1 and ...
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Subtracting 9 times the last digit from the rest gives a multiple of 7. (Works because (90 + 1) is divisible by 7.) 483: 48 − (3 × 9) = 21 = 7 × 3. Adding 3 times the first digit to the next and then writing the rest gives a multiple of 7. (This works because 10a + b − 7a = 3a + b; the last number has the same remainder as 10a + b.)