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  2. Bertrand's ballot theorem - Wikipedia

    en.wikipedia.org/wiki/Bertrand's_ballot_theorem

    The variant problem can be solved by the reflection method in a similar way to the original problem. The number of possible vote sequences is ( p + q q ) {\displaystyle {\tbinom {p+q}{q}}} . Call a sequence "bad" if the second candidate is ever ahead, and if the number of bad sequences can be enumerated then the number of "good" sequences can ...

  3. Bertrand paradox (probability) - Wikipedia

    en.wikipedia.org/wiki/Bertrand_paradox_(probability)

    The Bertrand paradox is a problem within the classical interpretation of probability theory. Joseph Bertrand introduced it in his work Calcul des probabilités (1889) [1] as an example to show that the principle of indifference may not produce definite, well-defined results for probabilities if it is applied uncritically when the domain of possibilities is infinite.

  4. Monty Hall problem - Wikipedia

    en.wikipedia.org/wiki/Monty_Hall_problem

    Thus the Bayes factor consists of the ratios ⁠ 1 / 2 ⁠ : 1 : 0 or equivalently 1 : 2 : 0, while the prior odds were 1 : 1 : 1. Thus, the posterior odds become equal to the Bayes factor 1 : 2 : 0. Given that the host opened door 3, the probability that the car is behind door 3 is zero, and it is twice as likely to be behind door 2 than door 1.

  5. Category:Probability problems - Wikipedia

    en.wikipedia.org/wiki/Category:Probability_problems

    Pages in category "Probability problems" The following 31 pages are in this category, out of 31 total. ... Bertrand's ballot theorem; Bertrand's box paradox;

  6. What would Proposition 1 do, and what would it not do? Learn ...

    www.aol.com/proposition-1-not-learn-ballot...

    Proposition 1 would change Idaho’s elections; here’s a look at how it would work. ... Idaho Statesman Opinion Editor Scott McIntosh will host a live debate about the ballot measure at 7 p.m ...

  7. Bertrand's box paradox - Wikipedia

    en.wikipedia.org/wiki/Bertrand's_box_paradox

    The probability of drawing another gold coin from the same box is 0 in (a), and 1 in (b) and (c). Thus, the overall probability of drawing a gold coin in the second draw is ⁠ 0 / 3 ⁠ + ⁠ 1 / 3 ⁠ + ⁠ 1 / 3 ⁠ = ⁠ 2 / 3 ⁠. The problem can be reframed by describing the boxes as each having one drawer on each of two sides. Each ...

  8. Fact check: Pencils are normally used to vote as ink can ...

    www.aol.com/fact-check-pencils-normally-used...

    The police investigated just 13 allegations of tampering with ballot papers during the 2019 general election, with only one leading to a conviction. This was after a person entered a polling ...

  9. KY AG’s office investigates after video of voting machine ...

    www.aol.com/ky-ag-office-investigates-video...

    Investigators from the Kentucky Attorney General's Office responded to a voting center in Laurel County on Thursday after a video showing a ballot-marking machine selecting the wrong option ...