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As an illustration of this, the parity cycle (1 1 0 0 1 1 0 0) and its sub-cycle (1 1 0 0) are associated to the same fraction 5 / 7 when reduced to lowest terms. In this context, assuming the validity of the Collatz conjecture implies that (1 0) and (0 1) are the only parity cycles generated by positive whole numbers (1 and 2 ...
There is no section on how 3n+1 conjecture may do anything with prime numbers; could use one. Example: proving 3n+1 conjecture means there is no infinite Nnext=(3n+1)/2 sequence of prime numbers that just won't stop appearing. Seriously, proving 3N+1 is real means proving curious sequences like this one are impossible.
Basically 3n+1 must, for all n, cross, intersect, or land on or something math-speak, a value that is also in 2^x where x is a natural number. How about, there is a non-empty intersection between the set of all numbers 2^x and any set of 3n+1 for any natural starting number n.
Suppose n is odd. Then 3n+1 is even. With probability 1/2 the next odd number is (3n+1)/2; So half of all even numbers have a single factor of 2. with probability 1/4, the next odd number is (3n+1)/4; So half the remaining even numbers have 2 factors of 2. with probability 1/8, the next odd number is (3n+1)/8;
Conjecture Field Comments Eponym(s) Cites 1/3–2/3 conjecture: order theory: n/a: 70 abc conjecture: number theory: ⇔Granville–Langevin conjecture, Vojta's conjecture in dimension 1 ⇒Erdős–Woods conjecture, Fermat–Catalan conjecture Formulated by David Masser and Joseph Oesterlé. [1] Proof claimed in 2012 by Shinichi Mochizuki: n/a ...
Turán also showed that a somewhat weaker assumption, the nonexistence of zeros with real part greater than 1 + N −1/2+ε for large N in the finite Dirichlet series above, would also imply the Riemann hypothesis, but Montgomery (1983) showed that for all sufficiently large N these series have zeros with real part greater than 1 + (log log N ...
However, 1 is a square mod 3 (equal to the square of both 1 and 2 mod 3), so there can be no similar identity for all values of that are congruent to 1 mod 3. More generally, as 1 is a square mod n {\displaystyle n} for all n > 1 {\displaystyle n>1} , there can be no complete covering system of modular identities for all n {\displaystyle n ...
The elements of a generating set of this semigroup are related to the sequence of numbers involved in the still open Collatz conjecture or the "3x + 1 problem". The 3x + 1 semigroup has been used to prove a weaker form of the Collatz conjecture. In fact, it was in such context the concept of the 3x + 1 semigroup was introduced by H. Farkas in ...