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  2. Perfect ring - Wikipedia

    en.wikipedia.org/wiki/Perfect_ring

    The following equivalent definitions of a left perfect ring R are found in Anderson and Fuller: [2]. Every left R-module has a projective cover.; R/J(R) is semisimple and J(R) is left T-nilpotent (that is, for every infinite sequence of elements of J(R) there is an n such that the product of first n terms are zero), where J(R) is the Jacobson radical of R.

  3. Krull–Schmidt category - Wikipedia

    en.wikipedia.org/wiki/Krull–Schmidt_category

    Let C be an additive category, or more generally an additive R-linear category for a commutative ring R. We call C a Krull–Schmidt category provided that every object decomposes into a finite direct sum of objects having local endomorphism rings. Equivalently, C has split idempotents and the endomorphism ring of every object is semiperfect.

  4. Semiperfect ring - Wikipedia

    en.wikipedia.org/?title=Semiperfect_ring&redirect=no

    Perfect ring#Semiperfect ring; This page is a redirect. The following categories are used to track and monitor this redirect: To a subtopic: ...

  5. Semi-local ring - Wikipedia

    en.wikipedia.org/wiki/Semi-local_ring

    The classical ring of quotients for any commutative Noetherian ring is a semilocal ring. The endomorphism ring of an Artinian module is a semilocal ring. Semi-local rings occur for example in algebraic geometry when a (commutative) ring R is localized with respect to the multiplicatively closed subset S = ∩ (R \ p i ) , where the p i are ...

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    The All-Clad Factory Seconds Sale just started: Get up to 73% off All-Clad cookware. AOL. ... Save 30% on Oprah and Gordon Ramsay's favorite cookware set. AOL. 11 of the very best women's pajamas ...

  7. All the things you wanted to know about Super Bowl rings but ...

    www.aol.com/finance/things-wanted-know-super...

    The jeweler, perhaps better known for its high school and college ring business, has made 38 of the 57 Super Bowl rings, including the very first, which was designed by Vince Lombardi himself.