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  2. DBSCAN - Wikipedia

    en.wikipedia.org/wiki/DBSCAN

    The low value of minPts = 1 does not make sense, as then every point is a core point by definition. With minPts ≤ 2, the result will be the same as of hierarchical clustering with the single link metric, with the dendrogram cut at height ε. Therefore, minPts must be chosen at least 3. However, larger values are usually better for data sets ...

  3. OPTICS algorithm - Wikipedia

    en.wikipedia.org/wiki/OPTICS_algorithm

    Like DBSCAN, OPTICS requires two parameters: ε, which describes the maximum distance (radius) to consider, and MinPts, describing the number of points required to form a cluster. A point p is a core point if at least MinPts points are found within its ε -neighborhood N ε ( p ) {\displaystyle N_{\varepsilon }(p)} (including point p itself).

  4. Local outlier factor - Wikipedia

    en.wikipedia.org/wiki/Local_outlier_factor

    Basic idea of LOF: comparing the local density of a point with the densities of its neighbors. A has a much lower density than its neighbors. The local outlier factor is based on a concept of a local density, where locality is given by k nearest neighbors, whose distance is used to estimate the density. By comparing the local density of an ...

  5. Talk:DBSCAN - Wikipedia

    en.wikipedia.org/wiki/Talk:DBSCAN

    GPL-V3 Java implementations of more than 80 data mining algorithms. It offers an efficient Java implementation of the DBScan algorithm using a KD-Tree that is easy to integrate in other Java software. A GUI and command line interface is provided. This is advertisement text.

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    www.aol.com/rihanna-wears-minidress-ripped...

    On the red carpet, she told Entertainment Tonight how proud she was of her partner, with whom she shares two children. “I left my kids [their sons RZA and Riot] to be here.I’m super proud of ...

  9. File:DBSCAN-Illustration.svg - Wikipedia

    en.wikipedia.org/wiki/File:DBSCAN-Illustration.svg

    Deutsch: Illustration von Clusteranalyse mit de:DBSCAN (minPts=3). Punkte bei A sind Kernpunkte, und bilden einen Cluster. Punkte bei A sind Kernpunkte, und bilden einen Cluster. Die Punkte B und C sind keine Kernpunkte, sind aber über die Objekte bei A dichte-verbunden und daher Teil dieses Clusters.