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At latitudes nearer the Equator, the outward centrifugal force produced by Earth's rotation is larger than at polar latitudes. This counteracts the Earth's gravity to a small degree – up to a maximum of 0.3% at the Equator – and reduces the apparent downward acceleration of falling objects.
If Earth's shape were perfectly known together with the exact mass density ρ = ρ(x, y, z), it could be integrated numerically (when combined with a reciprocal distance kernel) to find an accurate model for Earth's gravitational field. However, the situation is in fact the opposite: by observing the orbits of spacecraft and the Moon, Earth's ...
The object orbits the Sun but makes slow close approaches to the Earth–Moon system. Between 29 September (19:54 UTC) and 25 November 2024 (16:43 UTC) (a period of 1 month and 27 days) [4] it passed just outside Earth's Hill sphere (roughly 0.01 AU [1.5 million km; 0.93 million mi]) at a low relative velocity (in the range 0.002 km/s (4.5 mph) – 0.439 km/s [980 mph]) and became temporarily ...
In special relativity, parallel geodesics remain parallel. In a gravitational field with tidal effects, this will not, in general, be the case. If, for example, two bodies are initially at rest relative to each other, but are then dropped in the Earth's gravitational field, they will move towards each other as they fall towards the Earth's center.
[4] [verification needed] A more complex example is the one at right, the Earth's Hill sphere, which extends between the Lagrange points L 1 and L 2, [clarification needed] which lie along the line of centers of the Earth and the more massive Sun. [not verified in body] The gravitational influence of the less massive body is least in that ...
In classical mechanics, a gravitational field is a physical quantity. [5] A gravitational field can be defined using Newton's law of universal gravitation. Determined in this way, the gravitational field g around a single particle of mass M is a vector field consisting at every point of a vector pointing directly towards the particle. The ...
If a spacecraft placed at the Earth–Moon L 1 point is given even a slight nudge away from the equilibrium point, the spacecraft's trajectory will diverge away from the L 1 point. The entire system is in motion, so the spacecraft will not actually hit the Moon, but will travel in a winding path, off into space.
At a fixed point on the surface, the magnitude of Earth's gravity results from combined effect of gravitation and the centrifugal force from Earth's rotation. [2] [3] At different points on Earth's surface, the free fall acceleration ranges from 9.764 to 9.834 m/s 2 (32.03 to 32.26 ft/s 2), [4] depending on altitude, latitude, and longitude.