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Vanadium(V) chloride is the inorganic compound with the formula VCl 5. It is a black diamagnetic solid. The molecules adopt a bioctahedral structure similar to that of niobium(V) chloride .
From left: [V(H 2 O) 6] 2+ (lilac), [V(H 2 O) 6] 3+ (green), [VO(H 2 O) 5] 2+ (blue) and [VO(H 2 O) 5] 3+ (yellow).. Vanadium compounds are compounds formed by the element vanadium (V). The chemistry of vanadium is noteworthy for the accessibility of the four adjacent oxidation states 2–5, whereas the chemistry of the other group 5 elements, niobium and tantalum, are somewhat more limited to ...
From a microbial standpoint, the presence of natural chlorate could also explain why there is a variety of microorganisms capable of reducing chlorate to chloride. Further, the evolution of chlorate reduction may be an ancient phenomenon as all perchlorate reducing bacteria described to date also utilize chlorate as a terminal electron acceptor ...
Vanadium(III) chloride describes the inorganic compound with the formula VCl 3 and its hydrates. It forms a purple anhydrous form and a green hexahydrate [VCl 2 (H 2 O) 4 ]Cl·2H 2 O. These hygroscopic salts are common precursors to other vanadium(III) complexes and is used as a mild reducing agent .
Vanadyl acetylacetonate is the chemical compound with the formula VO(acac) 2, where acac – is the conjugate base of acetylacetone. It is a blue-green solid that dissolves in polar organic solvents. It is a blue-green solid that dissolves in polar organic solvents.
Vanadium chloride may refer to: Vanadium(II) chloride, VCl 2; Vanadium(III) chloride, VCl 3; Vanadium(IV) chloride, VCl 4; Vanadium(V) chloride, VCl 5
Vanadium(II) chloride is the inorganic compound with the formula VCl 2, and is the most reduced vanadium chloride. Vanadium(II) chloride is an apple-green solid that dissolves in water to give purple solutions.
It is the predominant vanadium(V) species in acidic solutions with pH between 0 and 2, and its salts are formed by protonation of vanadium(V) oxide in such solutions: [2] [3] V 2 O 5 + 2 H + → 2 VO + 2 + H 2 O (K = 3.42 × 10 −2) The ion can form a complex with a single aminopolycarboxylate ligand, [4] or with tridentate Schiff base ligands ...