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Here are additional clues for each of the words in today's Mini Crossword. NYT Mini Across Hints 1 Across: Food that many an N.Y.C. tourist grabs for breakfast — HINT: It starts with the letter "B"
SUDOKU. Play the USA TODAY Sudoku Game.. JUMBLE. Jumbles: VINYL GULCH RADISH OPAQUE. Answer: The pharaoh commissioned an artist to decorate his tomb. The result was — “HIRE-O-GLYPHICS”
Here are additional clues for each of the words in today's Mini Crossword. NYT Mini Across Hints 1 Across: Raygun or Moo Deng, in 2024 — HINT: It starts with the letter "M"
To illustrate, the solution + = has bases with a common factor of 3, the solution + = has bases with a common factor of 7, and + = + has bases with a common factor of 2. Indeed the equation has infinitely many solutions where the bases share a common factor, including generalizations of the above three examples, respectively
The clue may require arithmetic to be applied to another answer or answers (e.g. "25 across times 3" or "9 down minus 3 across") The clue may indicate possible answers but make it impossible to give the correct one without using crosslights (e.g. "A prime number") One answer may be related to another in a non-determinate way (e.g.
In the simple case of a function of one variable, say, h(x), we can solve an equation of the form h(x) = c for some constant c by considering what is known as the inverse function of h. Given a function h : A → B, the inverse function, denoted h −1 and defined as h −1 : B → A, is a function such that
Anacrostic may be the most accurate term used, and hence most common, as it is a portmanteau of anagram and acrostic, referencing the fact that the solution is an anagram of the clue answers, and the author of the quote is hidden in the clue answers acrostically.
Consider any primitive solution (x, y, z) to the equation x n + y n = z n. The terms in (x, y, z) cannot all be even, for then they would not be coprime; they could all be divided by two. If x n and y n are both even, z n would be even, so at least one of x n and y n are odd. The remaining addend is either even or odd; thus, the parities of the ...