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  2. Newton–Pepys problem - Wikipedia

    en.wikipedia.org/wiki/Newton–Pepys_problem

    The Newton–Pepys problem is a probability problem concerning the probability of throwing sixes from a certain number of dice. [1] In 1693 Samuel Pepys and Isaac Newton corresponded over a problem posed to Pepys by a school teacher named John Smith. [2] The problem was: Which of the following three propositions has the greatest chance of success?

  3. Dice pool - Wikipedia

    en.wikipedia.org/wiki/Dice_pool

    In many RPG systems, non-trivial actions often require dice rolls. Some RPGs roll a fixed number of dice, add a number to the die roll based on the character's attributes and skills, and compare the resulting number with a difficulty rating. In other systems, the character's attributes and skills determine the number of dice to be rolled.

  4. Examples of Markov chains - Wikipedia

    en.wikipedia.org/wiki/Examples_of_Markov_chains

    To see the difference, consider the probability for a certain event in the game. In the above-mentioned dice games, the only thing that matters is the current state of the board. The next state of the board depends on the current state, and the next roll of the dice. It does not depend on how things got to their current state.

  5. Bernoulli trial - Wikipedia

    en.wikipedia.org/wiki/Bernoulli_trial

    Graphs of probability P of not observing independent events each of probability p after n Bernoulli trials vs np for various p.Three examples are shown: Blue curve: Throwing a 6-sided die 6 times gives a 33.5% chance that 6 (or any other given number) never turns up; it can be observed that as n increases, the probability of a 1/n-chance event never appearing after n tries rapidly converges to 0.

  6. History of probability - Wikipedia

    en.wikipedia.org/wiki/History_of_probability

    Download as PDF; Printable version ... way to obtain (333), where the first, second and third dice all roll 3. There are a total of 27 permutations that sum to 10 but ...

  7. Mia (game) - Wikipedia

    en.wikipedia.org/wiki/Mia_(game)

    As an example, consider the roll 55. There are two rolls ranked above this (21 and 66), and so the probability that any single subsequent roll would beat 55 is the sum of the probability of rolling 21, which is 2 ⁄ 36, or rolling 66, which is 1 ⁄ 36. Therefore the probability of beating 55 outright on a subsequent roll is 3 ⁄ 36 or 8.3%.

  8. Probability interpretations - Wikipedia

    en.wikipedia.org/wiki/Probability_interpretations

    There are two broad categories [1] [2] of probability interpretations which can be called "physical" and "evidential" probabilities. Physical probabilities, which are also called objective or frequency probabilities, are associated with random physical systems such as roulette wheels, rolling dice and radioactive atoms. In such systems, a given ...

  9. Conditional independence - Wikipedia

    en.wikipedia.org/wiki/Conditional_independence

    Conditional independence depends on the nature of the third event. If you roll two dice, one may assume that the two dice behave independently of each other. Looking at the results of one die will not tell you about the result of the second die. (That is, the two dice are independent.)