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If the radii are equal, the radical axis is the line segment bisector of M 1, M 2. In any case the radical axis is a line perpendicular to ¯. On notations. The notation radical axis was used by the French mathematician M. Chasles as axe radical. [1] J.V. Poncelet used chorde ideale. [2]
The radical axis of a pair of circles is defined as the set of points that have equal power h with respect to both circles. For example, for every point P on the radical axis of circles 1 and 2, the powers to each circle are equal: h 1 = h 2. Similarly, for every point on the radical axis of circles 2 and 3, the powers must be equal, h 2 = h 3.
A pencil of circles (or coaxial system) is the set of all circles in the plane with the same radical axis. [9] To be inclusive, concentric circles are said to have the line at infinity as a radical axis. There are five types of pencils of circles, [10] the two families of Apollonian circles in the illustration above represent two of them.
The set of all points with () = is a line called radical axis. It contains possible common points of the circles and is perpendicular to line O 1 O 2 ¯ {\displaystyle {\overline {O_{1}O_{2}}}} . Secants theorem, chords theorem: common proof
The radical axis of two intersecting circles. The power diagram of the two circles is the partition of the plane into two halfplanes formed by this line. In the case n = 2, the power diagram consists of two halfplanes, separated by a line called the radical axis or chordale of the two circles. Along the radical axis, both circles have equal power.
The hyperbolic pencil defined by points C, D (the blue circles) has its radical axis on the perpendicular bisector of line CD, and all its circle centers on line CD. Inversive geometry, orthogonal intersection, and coordinate systems
Any initial two disjoint given circles can be rendered concentric as follows. The radical axis of the two given circles is constructed; choosing two arbitrary points P and Q on this radical axis, two circles can be constructed that are centered on P and Q and that intersect the two given circles orthogonally. These two constructed circles ...
Brianchon's theorem can be proved by the idea of radical axis or reciprocation. To prove it take an arbitrary length (MN) and carry it on the tangents starting from the contact points: PL = RJ = QH = MN etc. Draw circles a, b, c tangent to opposite sides of the hexagon at the created points (H,W), (J,V) and (L,Y) respectively.