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  2. Relate the image distance v, object distance u , image height h'...

    byjus.com/question-answer/relate-the-image-distance-v-object-distance-u-image...

    Determine the size (h'), magnification (m) and position of image (v) with proper signs? Assume object distance to be negative and object height to be positive. Q.

  3. A divergent lens has a focal length of - BYJU'S

    byjus.com/question-answer/a-divergent-lens-has-a-focal-length-of-20-cm-at-what...

    The focal length (f) of the divergent lens is, f = - 20 c m. (The focal length of the divergent or concave lens is negative) The image distance (v) from the lens is, v = - 10 c m. (In the case of concave lens, the image is always formed in front of the lens, so the image distance will be negative)

  4. Define the pole, the center of curvature, the radius of curvature...

    byjus.com/question-answer/define-pole-the-centre-of-curvature-the-radius-of...

    The radius of curvature: It is the radius of the sphere of which the mirror forms the part. It is represented by R. P C = R. Principal axis: The straight line joining the pole (P) and the centre of curvature. It is normal for the mirror at its pole.

  5. The same size images are formed by a convex lens when the ... -...

    byjus.com/question-answer/the-same-size-images-are-formed-by-a-convex-lens...

    The size of the image of an object, which is at infinity, as formed by a convex lens of focal length 30 cm is 2 cm. If a concave lens of focal length 20 cm is placed between the convex lens and the image at a distance of 26 cm from the convex lens, calculate the new size of the image

  6. An object is 2 m from a lens which forms an erect image one...

    byjus.com/.../an-object-is-2-m-from-a-lens-which-forms-an-erect-image-one-fourth

    A lens forms a virtual, erect and diminished image of an object placed at a distance of 2 m from it. The size of the image formed is half of that of the object. Which of the following statement is correct regarding the nature and focal length of the lens?

  7. An arrow 2.5 cm high is placed at a distance of 25 ... - BYJU'S

    byjus.com/question-answer/an-arrow-25-cm-high-is-placed-at-a-distance-of-25-cm...

    The magnification is given by the formula m = h 2 h 1 = - v u, where h 2 is the height of image, h 1 is height of object, v is distance of image from mirror and u is distance of object from mirror.

  8. To Find the Refractive Index of a Liquid by Using a Convex ...

    byjus.com/physics/determine-refractive-index-of-liquid-using-convex-lens

    Theory. Let us consider f1 and f2 to be the focal length of the glass convex lens and liquid lens respectively and let F be the focal length of their combination, then. \ (\begin {array} {l}\frac {1} {F}=\frac {1} {f_ {1}}+\frac {1} {f_ {2}}\end {array} \) From the lens maker’s formula. We have,

  9. Learn how to use polar to rectangular calculator with a step-by-step procedure. Get the polar to rectangular calculator available online for free only at BYJU'S.

  10. NCERT Solutions for Class 11 Physics Chapter 6 - BYJU'S

    byjus.com/ncert-solutions-class-11-physics/chapter-6-work-energy-and-power

    NCERT Solutions Class 11 Physics Chapter 6 Work, Energy and Power are provided in PDF format for easy access and download. Students can get answers to the textbook questions, extra questions, exemplary problems and worksheets, which will help them to get well-versed in the topics covered in this chapter.

  11. Short answer type question. Explain Lenins April Theses. - BYJU'S

    byjus.com/question-answer/short-answer-type-question-explain-lenins-april-theses

    Solution. Lenin was the leader of the Bolshevik party. He returned to Russia and put three demands which were known as Lenin’s April Theses. They were: (i) The First World War be brought to an end. (ii) Land must be transferred to the peasants. (iii) The banks should be nationalised. Suggest Corrections. 429.