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The International Mathematical Olympiad (IMO) is a mathematical olympiad for pre-university students, and is the oldest of the International Science Olympiads. [1] It is widely regarded as the most prestigious mathematical competition in the world. The first IMO was held in Romania in 1959. It has since been held annually, except in 1980.
The Asian Pacific Mathematics Olympiad; IMO selection exams in the AMOC Selection School in April; The Australian Mathematical Olympiad (AMO) is held annually in the second week of February. It is composed of two four-hour papers held over two consecutive days. There are four questions in each exam for a total of eight questions.
The following IMO participants have either received a Fields Medal, an Abel Prize, a Wolf Prize or a Clay Research Award, awards which recognise groundbreaking research in mathematics; a European Mathematical Society Prize, an award which recognizes young researchers; or one of the American Mathematical Society's awards (a Blumenthal Award in ...
Logo of the International Mathematical Olympiad. The first of the International Mathematical Olympiads (IMOs) was held in Romania in 1959. The oldest of the International Science Olympiads, the IMO has since been held annually, except in 1980.
The selection process takes place over the course of roughly five stages. At the last stage, the US selects six members to form the IMO team. There are three AMC competitions held each year: the AMC 8, for students under the age of 14.5 and in grades 8 and below [1] the AMC 10, for students under the age of 17.5 and in grades 10 and below
Rank Country Gold Silver Bronze Honorable mentions Gold in Last 10 contests (updated till 2024) 1 China: 185 37 6 0 51 2 United States [2]: 151 120 30
Canadian Mathematical Olympiad — competition whose top performers represent Canada at the International Mathematical Olympiad The Centre for Education in Mathematics and Computing (CEMC) based out of the University of Waterloo hosts long-standing national competitions for grade levels 7–12 [ 2 ] [ 3 ]
This method can be applied to problem #6 at IMO 1988: Let a and b be positive integers such that ab + 1 divides a 2 + b 2. Prove that a 2 + b 2 / ab + 1 is a perfect square. Let a 2 + b 2 / ab + 1 = q and fix the value of q. If q = 1, q is a perfect square as desired. If q = 2, then (a-b) 2 = 2 and there is no integral solution ...