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Frobenius coin problem with 2-pence and 5-pence coins visualised as graphs: Sloping lines denote graphs of 2x+5y=n where n is the total in pence, and x and y are the non-negative number of 2p and 5p coins, respectively. A point on a line gives a combination of 2p and 5p for its given total (green).
The word problem for an algebra is then to determine, given two expressions (words) involving the generators and operations, whether they represent the same element of the algebra modulo the identities. The word problems for groups and semigroups can be phrased as word problems for algebras. [1]
For example, in detecting a dissimilar coin in three weighings ( = ), the maximum number of coins that can be analyzed is = .Note that with weighings and coins, it is not always possible to determine the nature of the last coin (whether it is heavier or lighter than the rest), but only that the other coins are all the same, implying that the last coin is the ...
For instance, if the one solving the math word problem has a limited understanding of the language (English, Spanish, etc.) they are more likely to not understand what the problem is even asking. In Example 1 (above), if one does not comprehend the definition of the word "spent," they will misunderstand the entire purpose of the word problem.
There seems to be a discrepancy, as there cannot be two answers ($29 and $30) to the math problem. On the one hand it is true that the $25 in the register, the $3 returned to the guests, and the $2 kept by the bellhop add up to $30, but on the other hand, the $27 paid by the guests and the $2 kept by the bellhop add up to only $29.
Coins in a fountain is a problem in combinatorial mathematics that involves a generating function.In this problem, a fountain is an arrangement of non-overlapping unit circles into horizontal rows in the plane so that consecutive circles in the bottom row are tangent to each other, and such that each circle in a higher row is tangent to two coins from the next row below it.