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Stable even–even nuclides number as many as three isobars for some mass numbers, and up to seven isotopes for some atomic numbers. Conversely, of the 251 known stable nuclides, only five have both an odd number of protons and odd number of neutrons: hydrogen-2 , lithium-6, boron-10, nitrogen-14, and tantalum-180m.
Indium has 39 known isotopes, ranging in mass number from 97 to 135. Only two isotopes occur naturally as primordial nuclides: indium-113, the only stable isotope, and indium-115, which has a half-life of 4.41 × 10 14 years, four orders of magnitude greater than the age of the Universe and nearly 30,000 times greater than half life of thorium ...
Indium (49 In) consists of two primordial nuclides, with the most common (~ 95.7%) nuclide (115 In) being measurably though weakly radioactive. Its spin-forbidden decay has a half-life of 4.41×10 14 years, much longer than the currently accepted age of the Universe. The stable isotope 113 In is only 4.3% of
Indium-111 (111 In) is a radioactive isotope of indium (In). It decays by electron capture to stable cadmium-111 with a half-life of 2.8 days. [3] Indium-111 chloride (111 InCl) solution is produced by proton irradiation of a cadmium target (112 Cd(p,2n) or 111 Cd(p,n)) in a cyclotron, as recommended by International Atomic Energy Agency (IAEA). [4]
isotope half-life 10 −24 seconds ; hydrogen-5: 86(6) lithium-4: 91(9) hydrogen-4: 139(10) nitrogen-10: 143(36) oxygen-11: 198(12) helium-10: 260(40) hydrogen-6: 294(67) lithium-5
The only stable nuclides having an odd number of protons and an odd number of neutrons are hydrogen-2, lithium-6, boron-10, nitrogen-14 and (observationally) tantalum-180m. This is because the mass–energy of such atoms is usually higher than that of their neighbors on the same isobaric chain, so most of them are unstable to beta decay.
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The number of protons (Z column) and number of neutrons (N column). energy column The column labeled "energy" denotes the energy equivalent of the mass of a neutron minus the mass per nucleon of this nuclide (so all nuclides get a positive value) in MeV , formally: m n − m nuclide / A , where A = Z + N is the mass number.