Ad
related to: fehling's a and b solution manual youtube
Search results
Results From The WOW.Com Content Network
Fehling's solution is prepared by combining two separate solutions: Fehling's A, which is a deep blue aqueous solution of copper(II) sulfate, and Fehling's B, which is a colorless solution of aqueous potassium sodium tartrate (also known as Rochelle salt) made strongly alkaline with sodium hydroxide. These two solutions, stable separately, are ...
Hermann von Fehling was born in Lübeck.With the intention of taking up pharmacy he entered Heidelberg University about 1835. After graduating he went to Gießen as preparateur to Justus von Liebig, with whom he elucidated the composition of paraldehyde and metaldehyde.
The nature of the complex formed in Fehling's solution is [Cu(L-tartH-2) 2] 6-(tart = tartrate) Therefore, all hydroxyl groups are deprotonated and the ball and stick model showed in the article is false. Moreover, L-tartaric acid is used to prepare Fehling's solution, so the citation of the publication dealing with complex compounds of copper ...
Image credits: Vast_Sweet_1221 #8. In my car, I always keep a lighter, canned/bottled water, a change of clothes, an old (but functional) pair of shoes, and a phone charging cord.
An 8-year-old boy with Down syndrome became a hero after he alerted his 14-year-old sister of a fire in their Colorado home, helping them get out on time before it was engulfed in flames.
Lando Norris got McLaren the constructor’s championship. Norris won Sunday’s Abu Dhabi Grand Prix from the pole position ahead of Ferrari’s Carlos Sainz and Charles Leclerc.
It is advised to check the references for photos of reaction results. [1] Reagent testers might show the colour of the desired substance while not showing a different colour for a more dangerous additive. [2]
One maltose will reduce two Cu 2+ in the Fehling reaction. The concentration of Cu 2+ in Fehling’s solution is 0.14 M, which is capable of oxidizing 0.070 M maltose. 5 mL of Fehling’s solution can oxidize 0.070 M x 0.005 L = 0.00035 moles of maltose. A 100 °L malt extract produces 0.00035 mol maltose in 60 min, or 5.8 μmol/min, or 5.8 IU ...