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  2. Integer factorization - Wikipedia

    en.wikipedia.org/wiki/Integer_factorization

    Given an integer n that will be factored, where n is an odd positive integer greater than a certain constant. In this factoring algorithm the discriminant Δ is chosen as a multiple of n, Δ = −dn, where d is some positive multiplier. The algorithm expects that for one d there exist enough smooth forms in G Δ.

  3. Integer factorization records - Wikipedia

    en.wikipedia.org/wiki/Integer_factorization_records

    Integer factorization is the process of determining which prime numbers divide a given positive integer.Doing this quickly has applications in cryptography.The difficulty depends on both the size and form of the number and its prime factors; it is currently very difficult to factorize large semiprimes (and, indeed, most numbers that have no small factors).

  4. Shor's algorithm - Wikipedia

    en.wikipedia.org/wiki/Shor's_algorithm

    As far as is known, this is not possible using classical (non-quantum) computers; no classical algorithm is known that can factor integers in polynomial time. However, Shor's algorithm shows that factoring integers is efficient on an ideal quantum computer, so it may be feasible to defeat RSA by constructing a large quantum computer.

  5. RSA Factoring Challenge - Wikipedia

    en.wikipedia.org/wiki/RSA_Factoring_Challenge

    The computer's hard drive was subsequently destroyed so that no record would exist, anywhere, of the solution to the factoring challenge. [ 6 ] The first RSA numbers generated, RSA-100 to RSA-500 and RSA-617, were labeled according to their number of decimal digits; the other RSA numbers (beginning with RSA-576) were generated later and ...

  6. Fermat's factorization method - Wikipedia

    en.wikipedia.org/wiki/Fermat's_factorization_method

    Fermat's factorization method, named after Pierre de Fermat, is based on the representation of an odd integer as the difference of two squares: =. That difference is algebraically factorable as (+) (); if neither factor equals one, it is a proper factorization of N.

  7. 10 Hard Math Problems That Even the Smartest People in the ...

    www.aol.com/10-hard-math-problems-even-150000090...

    Goldbach’s Conjecture. One of the greatest unsolved mysteries in math is also very easy to write. Goldbach’s Conjecture is, “Every even number (greater than two) is the sum of two primes ...

  8. 4 Pics 1 Word Cheats- Answering Difficult Puzzles - AOL

    www.aol.com/news/2013-02-20-4-pics-1-word-cheats...

    Warning: This article contains spoilers. 4 Pics 1 Word continues to delight and frustrate us. Occasionally, we'll rattle off four to five puzzles with little effort before getting stuck for ...

  9. General number field sieve - Wikipedia

    en.wikipedia.org/wiki/General_number_field_sieve

    Since f is of degree d with integer coefficients, if a and b are integers, then so will be b d ·f(a/b), which we call r. Similarly, s = b e · g ( a / b ) is an integer. The goal is to find integer values of a and b that simultaneously make r and s smooth relative to the chosen basis of primes.