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Then the resistance seen by the test voltage is found using the circuit in the right panel of Figure 1 and is simply V X / I X = R 1. Form the product C 1 R 1. Add these terms. In effect, it is as though each capacitor charges and discharges through the resistance found in the circuit when the other capacitor is an open circuit.
In the short-time limit, if the capacitor starts with a certain voltage V, since the voltage drop on the capacitor is known at this instant, we can replace it with an ideal voltage source of voltage V. Specifically, if V=0 (capacitor is uncharged), the short-time equivalence of a capacitor is a short circuit.
The bootstrap circuit uses a coupling capacitor, formed from the gate/source capacitance of a transistor, to drive a signal line to slightly greater than the supply voltage. [10] Some all-pMOS integrated circuits such as the Intel 4004 and the Intel 8008 use that 2-transistor "bootstrap load" circuit. [11] [12] [13]
They can be performed on a circuit involving capacitors and inductors as well, by expressing circuit elements as impedances and sources in the frequency domain. In general, the concept of source transformation is an application of Thévenin's theorem to a current source , or Norton's theorem to a voltage source .
A capacitor-input filter is a filter circuit in which the first element is a capacitor connected in parallel with the output of the rectifier in a linear power supply. The capacitor increases the DC voltage and decreases the ripple voltage components of the output. [1] The capacitor is often referred to as a smoothing capacitor or reservoir ...
A simple switched-capacitor parasitic-sensitive integrator. Switched-capacitor simulated resistors can replace the input resistor in an op amp integrator to provide accurate voltage gain and integration. One of the earliest of these circuits is the parasitic-sensitive integrator developed by the Czech engineer Bedrich Hosticka. [3]
The following formulae use it, assuming a constant voltage applied across the capacitor and resistor in series, to determine the voltage across the capacitor against time: Charging toward applied voltage (initially zero voltage across capacitor, constant V 0 across resistor and capacitor together) V 0 : V ( t ) = V 0 ( 1 − e − t / τ ...
Figure 2B shows a circuit electrically identical to Figure 2A using Miller's theorem. The coupling capacitor is replaced on the input side of the circuit by the Miller capacitance , which draws the same current from the driver as the coupling capacitor in Figure 2A. Therefore, the driver sees exactly the same loading in both circuits.
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