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  2. Pandiagonal magic square - Wikipedia

    en.wikipedia.org/wiki/Pandiagonal_magic_square

    Consider the sum 1+2+3+5+6+7 = 24. This sum can be divided in half by taking the appropriate groups of three addends, or in thirds using groups of two addends: 1+5+6 = 2+3+7 = 12 1+7 = 2+6 = 3+5 = 8. An additional equal partitioning of the sum of squares guarantees the semi-bimagic property noted below: 1 2 + 5 2 + 6 2 = 2 2 + 3 2 + 7 2 = 62

  3. Template:Sum - Wikipedia

    en.wikipedia.org/wiki/Template:Sum

    This template performs addition. For example, if you want to add 2 and 3, use this: {{sum | 2 | 3}}, which creates 5. It handles positive and negative integers, fractions, and decimals to thirteen decimal points: {{sum |-3 | 1}} produces: -2 {{sum | 1 | 0.5}} produces: 1.5 {{sum | 1 | 2/3}} produces: 1.6666666666667; It also handles some ...

  4. Template:Sum/doc - Wikipedia

    en.wikipedia.org/wiki/Template:Sum/doc

    Main page; Contents; Current events; Random article; About Wikipedia; Contact us

  5. Magic square - Wikipedia

    en.wikipedia.org/wiki/Magic_square

    Also the four corners of any 5×5 square and the central cell, as well as the middle cells of each side together with the central cell, including wrap around, give the magic sum: 13+10+19+22+1 and 20+24+12+8+1. Lastly the four rhomboids that form elongated crosses also give the magic sum: 23+1+9+24+8, 15+1+17+20+12, 14+1+18+13+19, 7+1+25+22+10 ...

  6. File:I-20-sample.pdf - Wikipedia

    en.wikipedia.org/wiki/File:I-20-sample.pdf

    Printable version; Page information; ... English: Form I-20, Certificate of Eligibility for Nonimmigrant ... Version of PDF format: 1.5

  7. Divisor sum identities - Wikipedia

    en.wikipedia.org/wiki/Divisor_sum_identities

    The purpose of this page is to catalog new, interesting, and useful identities related to number-theoretic divisor sums, i.e., sums of an arithmetic function over the divisors of a natural number , or equivalently the Dirichlet convolution of an arithmetic function () with one: