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  2. Straightedge and compass construction - Wikipedia

    en.wikipedia.org/wiki/Straightedge_and_compass...

    Angle trisection is the construction, using only a straightedge and a compass, of an angle that is one-third of a given arbitrary angle. This is impossible in the general case. For example, the angle 2 π /5 radians (72° = 360°/5) can be trisected, but the angle of π /3 radians (60°) cannot be trisected. [8]

  3. Angle trisection - Wikipedia

    en.wikipedia.org/wiki/Angle_trisection

    Angles may be trisected via a neusis construction using tools beyond an unmarked straightedge and a compass. The example shows trisection of any angle θ > ⁠ 3π / 4 ⁠ by a ruler with length equal to the radius of the circle, giving trisected angle φ = ⁠ θ / 3 ⁠.

  4. Heptadecagon - Wikipedia

    en.wikipedia.org/wiki/Heptadecagon

    As 17 is a Fermat prime, the regular heptadecagon is a constructible polygon (that is, one that can be constructed using a compass and unmarked straightedge): this was shown by Carl Friedrich Gauss in 1796 at the age of 19. [1] This proof represented the first progress in regular polygon construction in over 2000 years. [1]

  5. Heptagon - Wikipedia

    en.wikipedia.org/wiki/Heptagon

    This type of construction is called a neusis construction. It is also constructible with compass, straightedge and angle trisector . The impossibility of straightedge and compass construction follows from the observation that 2 cos ⁡ 2 π 7 ≈ 1.247 {\displaystyle \scriptstyle {2\cos {\tfrac {2\pi }{7}}\approx 1.247}} is a zero of the ...

  6. Category:Compass and straightedge constructions - Wikipedia

    en.wikipedia.org/wiki/Category:Compass_and...

    Pages in category "Compass and straightedge constructions" The following 10 pages are in this category, out of 10 total. This list may not reflect recent changes .

  7. Constructions in hyperbolic geometry - Wikipedia

    en.wikipedia.org/wiki/Constructions_in...

    Construct the line segment BB' and using a hyperbolic ruler, construct the line OI" such that OI" is perpendicular to BB' and parallel to B'I". Then, line OA is the angle bisector for ᗉ IAI'. [3] Case 2c: IB' is ultraparallel to I'B. Using the ultraparallel theorem, construct the common perpendicular of IB' and I'B, CC'. Let the intersection ...

  8. Constructible number - Wikipedia

    en.wikipedia.org/wiki/Constructible_number

    The square root of 2 is equal to the length of the hypotenuse of a right triangle with legs of length 1 and is therefore a constructible number. In geometry and algebra, a real number is constructible if and only if, given a line segment of unit length, a line segment of length | | can be constructed with compass and straightedge in a finite number of steps.

  9. 65537-gon - Wikipedia

    en.wikipedia.org/wiki/65537-gon

    The regular 65537-gon (one with all sides equal and all angles equal) is of interest for being a constructible polygon: that is, it can be constructed using a compass and an unmarked straightedge. This is because 65,537 is a Fermat prime , being of the form 2 2 n + 1 (in this case n = 4).