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PdCl 2 + 2 PPh 3 → PdCl 2 (PPh 3) 2 PdCl 2 (PPh 3) 2 + 2 PPh 3 + 5 ⁄ 2 N 2 H 4 → Pd(PPh 3) 4 + 1 ⁄ 2 N 2 + 2 N 2 H 5 Cl. Both steps may be carried out in a one-pot reaction, without isolating and purifying the PdCl 2 (PPh 3) 2 intermediate. [5] Reductants other than hydrazine can be employed, including ascorbic acid. [6]
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