Search results
Results From The WOW.Com Content Network
Lead perchlorate trihydrate is produced by the reaction of lead(II) oxide, lead carbonate, or lead nitrate by perchloric acid: . Pb(NO 3) 2 + HClO 4 → Pb(ClO 4) 2 + HNO 3. The excess perchloric acid was removed by first heating the solution to 125 °C, then heating it under moist air at 160 °C to remove the perchloric acid by converting the acid to the dihydrate.
Lead(II) chloride is the main precursor for organometallic derivatives of lead, such as plumbocenes. [11] The usual alkylating agents are employed, including Grignard reagents and organolithium compounds: 2 PbCl 2 + 4 RLi → R 4 Pb + 4 LiCl + Pb 2 PbCl 2 + 4 RMgBr → R 4 Pb + Pb + 4 MgBrCl 3 PbCl 2 + 6 RMgBr → R 3 Pb-PbR 3 + Pb + 6 MgBrCl [12]
Lead(II) sulfate is poorly soluble, as can be seen in the following diagram showing addition of SO 2− 4 to a solution containing 0.1 M of Pb 2+. The pH of the solution is 4.5, as above that, Pb 2+ concentration can never reach 0.1 M due to the formation of Pb(OH) 2. Observe that Pb 2+ solubility drops 10,000 fold as SO 2− 4 reaches 0.1 M.
The following chart shows the solubility of various ionic compounds in water at 1 atm pressure and room temperature (approx. 25 °C, 298.15 K). "Soluble" means the ionic compound doesn't precipitate, while "slightly soluble" and "insoluble" mean that a solid will precipitate; "slightly soluble" compounds like calcium sulfate may require heat to precipitate.
It is then converted to the ammonium salt (NH 4) 2 PbCl 6 by adding ammonium chloride (NH 4 Cl). Finally, the solution is treated with concentrated sulfuric acid H 2 SO 4, to separate out lead tetrachloride. This series of reactions is conducted at 0 °C. The following equations illustrate the reaction: PbCl 2 + 2HCl + Cl 2 → H 2 PbCl 6
11.3 Li. 12 M. Toggle M subsection. 12.1 Mg. ... Lead(II) azide – Pb(N 3) 2; Lead(II) bromide – PbBr 2; Lead(II) ... Sodium iodide – NaI; Sodium manganate ...
PbCl 2, PbBr 2 and PbI 2 are commonly used to produce donor centers. Other n-type doping agents such as Bi 2 Te 3 , TaTe 2 , MnTe 2 , will substitute for Pb and create uncharged vacant Pb-sites. These vacant sites are subsequently filled by atoms from the lead excess and the valence electrons of these vacant atoms will diffuse through crystal.
3 Pb 2 CO 3 (OH) 2 + O 2 → 2 Pb 3 O 4 + 3 CO 2 + 3 H 2 O. In solution, lead(II,IV) oxide can be prepared by reaction of potassium plumbate with lead(II) acetate, yielding yellow insoluble lead(II,IV) oxide monohydrate Pb 3 O 4 ·H 2 O, which can be turned into the anhydrous form by gentle heating: K 2 PbO 3 + 2 Pb(OCOCH 3) 2 + H 2 O → Pb 3 ...