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2. These 7 flattering dresses are 50% off at Old Navy — but not ...

   www.aol.com/lifestyle/these-7-flattering-dresses...

   There are tons of deals for the whole family, like 50% off activewear for the whole family, plus swim, PJs and more, because everything, and we mean everything at Old Navy is 50% off.

3. FYI, you can get 50% off everything at Old Navy right now

   www.aol.com/lifestyle/you-can-get-half-off...

   Old Navy's "Giftober" event is underway, which means nw through Wednesday, Oct. 23 you can save 50% — yes, half-off! — absolutely everything at Old Navy.We're talking matching PJs for the ...

4. Everything at Old Navy is still 50% off for extended Cyber ...

   www.aol.com/lifestyle/everything-at-old-navy-is...

   The good news is that Old Navy is running 50% off the entire site during Cyber Monday. The bad news is that it ends at midnight — and lots of our favorite styles are already sold out.

5. Buy one, get one free - Wikipedia

   en.wikipedia.org/wiki/Buy_one,_get_one_free

   The economist Alex Tabarrok has argued, that the success of this promotion lies in the fact that consumers value the first unit significantly more than the second one. So compared to a seemingly equivalent "Half price off" promotion, they may only buy one item at half price, because the value they attach to the second unit is lower than even the discounted price.

6. Navy blue - Wikipedia

   en.wikipedia.org/wiki/Navy_blue

   Navy blue is a dark shade of the color blue.. French sailor in dark blue uniform. Navy blue got its name from the dark blue (contrasted with naval white) worn by officers in the Royal Navy since 1748 and subsequently adopted by other navies around the world.

7. Coupon collector's problem - Wikipedia

   en.wikipedia.org/wiki/Coupon_collector's_problem

   An alternative statement is: given n coupons, how many coupons do you expect you need to draw with replacement before having drawn each coupon at least once? The mathematical analysis of the problem reveals that the expected number of trials needed grows as Θ ( n log ⁡ ( n ) ) {\displaystyle \Theta (n\log(n))} .