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The Coleman–Liau index is calculated with the following formula: = L is the average number of letters per 100 words and S is the average number of sentences per 100 words. Note that the multiplication operator is often omitted (as is common practice in mathematical formulas when it is clear that multiplication is implied).
The #if function selects one of two alternatives based on the truth value of a test string. {{#if: test string | value if true | value if false}} As explained above, a string is considered true if it contains at least one non-whitespace character. Any string containing only whitespace or no characters at all will be treated as false.
Data might include the string of text hello world, the number 5 or the date 10-Sep-97. A formula would begin with the equals sign, =5*3, but this would normally be invisible because the display shows the result of the calculation, 15 in this case, not the formula itself. This may lead to confusion in some cases.
In the second line, the number one is added to the fraction, and again Excel displays only 15 figures. In the third line, one is subtracted from the sum using Excel. Because the sum has only eleven 1s after the decimal, the true difference when ‘1’ is subtracted is three 0s followed by a string of eleven 1s.
In a classification task, the precision for a class is the number of true positives (i.e. the number of items correctly labelled as belonging to the positive class) divided by the total number of elements labelled as belonging to the positive class (i.e. the sum of true positives and false positives, which are items incorrectly labelled as belonging to the class).
It scans the text and extracts the words contained in it. It then compares each word with a known list of correctly spelled words (i.e. a dictionary). This might contain just a list of words, or it might also contain additional information, such as hyphenation points or lexical and grammatical attributes.
Not to worry — here’s a quick breakdown of how to write numbers in words on a check. ... You put $900 in the number box but accidentally wrote “Nine thousand and 00/100” on the text line ...
Given a complex number z, there is not a unique complex number w satisfying erf w = z, so a true inverse function would be multivalued. However, for −1 < x < 1 , there is a unique real number denoted erf −1 x satisfying erf ( erf − 1 x ) = x . {\displaystyle \operatorname {erf} \left(\operatorname {erf} ^{-1}x\right)=x.}