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Mixed-mode simulation is handled on three levels: with primitive digital elements that use timing models and the built-in 12 or 16 state digital logic simulator, with subcircuit models that use the actual transistor topology of the integrated circuit, and finally, with inline Boolean logic expressions.
Figure 2.Greinacher circuit. The Greinacher voltage doubler is a significant improvement over the Villard circuit for a small cost in additional components. The ripple is much reduced, nominally zero under open-circuit load conditions, but when current is being drawn depends on the resistance of the load and the value of the capacitors used.
To model the nonideal behavior of a real circuit component may require a combination of multiple ideal electrical elements to approximate its function. For example, an inductor circuit element is assumed to have inductance but no resistance or capacitance, while a real inductor, a coil of wire, has some resistance in addition to its inductance ...
A capacitance multiplier is designed to make a capacitor function like a much larger capacitor. This can be achieved in at least two ways. An active circuit, using a device such as a transistor or operational amplifier; A passive circuit, using autotransformers. These are typically used for calibration standards.
Digital circuit responses are often used to populate databases for signal delay and loading calculation such as: timing analysis; power analysis; circuit simulation; and signal integrity analysis. Analog circuits are often run in detailed test benches to indicate if the extra extracted parasitics will still allow the designed circuit to function.
It is applicable to electronic circuits in which the AC signals (i.e., the time-varying currents and voltages in the circuit) are small relative to the DC bias currents and voltages. A small-signal model is an AC equivalent circuit in which the nonlinear circuit elements are replaced by linear elements whose values are given by the first-order ...
Form the product C 2 ( R 1 + R 2). Select capacitor C 1, replace it by a test voltage V X, and replace C 2 by an open circuit. Then the resistance seen by the test voltage is found using the circuit in the right panel of Figure 1 and is simply V X / I X = R 1. Form the product C 1 R 1. Add these terms.
The term n(n+1) U f represents the sum of voltage losses caused by diodes, over all capacitors on the output side (i.e. on the right side in the example ‒ C 2 and C 4). For example if we have 2 stages like in the example, the total loss is 2+4 = 2*(2+1) = 6 times U f .