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compare two doubles, -1 on NaN dconst_0 0e 0000 1110 → 0.0 push the constant 0.0 (a double) onto the stack dconst_1 0f 0000 1111 → 1.0 push the constant 1.0 (a double) onto the stack ddiv 6f 0110 1111 value1, value2 → result divide two doubles dload 18 0001 1000 1: index → value load a double value from a local variable #index: dload_0 26
Push the length (of type native unsigned int) of array on the stack. Object model instruction 0xFE 0x0C ldloc <uint16 (indx)> Load local variable of index indx onto stack. Base instruction 0x06 ldloc.0: Load local variable 0 onto stack. Base instruction 0x07 ldloc.1: Load local variable 1 onto stack. Base instruction 0x08 ldloc.2
COBOL: String constants may be continued by not ending the original string in a PICTURE clause with ', then inserting a -in column 7 (same position as the * for comment is used.) TUTOR: Lines starting with a tab (after any indentation required by the context) continue the prior command.
Go's foreach loop can be used to loop over an array, slice, string, map, ... // loop over the range 1..4 ... Invoke a hypothetical frob command three times, ...
interface StringManipulator {String extendString (String input); // A method which is optional to implement default String shortenString (String input) {return input. substring (1);}} // This is a valid class despite not implementing all the methods class PartialStringManipulator implements StringManipulator {@Override public String ...
Granted that the loop variable's value is defined after the termination of the loop, then the above statement will find the first non-positive element in array A (and if no such, its value will be N + 1), or, with suitable variations, the first non-blank character in a string, and so on.
LOOP is a simple register language that precisely captures the primitive recursive functions. [1] The language is derived from the counter-machine model . Like the counter machines the LOOP language comprises a set of one or more unbounded registers , each of which can hold a single non-negative integer.
for X := 0.1 step 0.1 to 1.0 do might be repeated 9 or 10 times, depending on rounding errors and/or the hardware and/or the compiler version. Furthermore, if the increment of X occurs by repeated addition, accumulated rounding errors may mean that the value of X in each iteration can differ quite significantly from the expected sequence 0.1, 0 ...