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A pound-foot (lb⋅ft), abbreviated from pound-force foot (lbf · ft), is a unit of torque representing one pound of force acting at a perpendicular distance of one foot from a pivot point. [2] Conversely one foot pound-force (ft · lbf) is the moment about an axis that applies one pound-force at a radius of one foot.
Nm N⋅m 1 Nm lbft; Nm lbfft; Non-SI metric: kilogram-metre: kgm kg·m 9.80665 Imperial & US customary: pound-foot: lbft lb⋅ft Pound-inch (lb.in) is also available 1.3558 Scientific: SI: newton metre: Nm N⋅m 1 Nm lbft; Nm lbfft; Non-SI metric: kilogram-force metre: kgf.m kgf⋅m 9.80665 Imperial & US customary: pound-foot: lbfft lb-fft lbf ...
lb⋅ft 1.0 lb⋅ft (1.4 N⋅m) lb.ft Nm; lb.ft kg-m; Scientific: SI: newton-metre: N.m N⋅m Triple combinations are also possible. See the full list. 1.0 N⋅m (0.74 lbf⋅ft) N.m kgf.m; N.m lbf.ft; Non-SI metric: kilogram force-metre: kgf.m kgf⋅m 1.0 kgf⋅m (9.8 N⋅m; 7.2 lbf⋅ft) kgf.m N.m; kgf.m lbf.ft; Imperial & US customary: pound ...
The foot-pound force (symbol: ft⋅lbf, [1] ft⋅lb f, [2] or ft⋅lb [3]) is a unit of work or energy in the engineering and gravitational systems in United States customary and imperial units of measure. It is the energy transferred upon applying a force of one pound-force (lbf) through a linear displacement of one foot.
In the US, torque is most commonly referred to as the foot-pound (denoted as either lb-ft or ft-lb) and the inch-pound (denoted as in-lb). [ 17 ] [ 18 ] Practitioners depend on context and the hyphen in the abbreviation to know that these refer to torque and not to energy or moment of mass (as the symbolism ft-lb would properly imply).
NM (Adm); nmi (Adm) = 6080 ft = 1 853.184 m: ... ≡ 1 ⁄ 400 of a revolution ≡ ... foot-pound-force per second: ft⋅lbf/s ≡ 1 ft lbf/s
The numerical designations usually indicate the maximum torque rating of the gearbox in newton metres. For example, the F40 gearbox is rated at 400 Nm or 295 ft-lbs torque; the M32 gearbox is rated at 320 Nm; the F17 gearbox is rated at 170 Nm, and so on.
{{convert|4|ft|0|adj=mid|-long}} → 4-foot-long (1 m) The last example works because " |0 " sets the output precision to zero, and convert does not look for an output unit once the precision has been specified because a precision is always given after the output unit, if any.