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The conversion procedure for some units (for example, the Mach unit of speed) are built into Module:Convert as they are too complex to be specified in a table. That is indicated by entering a code (which must be the same as used in the module) in the Extra column.
If a comet with this speed fell to the Earth it would gain another 63 MJ/kg, yielding a total of 2655 MJ/kg with a speed of 72.9 km/s. Since the equator is moving at about 0.5 km/s, the impact speed has an upper limit of 73.4 km/s, giving an upper limit for the specific energy of a comet hitting the Earth of about 2690 MJ/kg.
The watt, kilogram, joule, and the second are part of the International System of Units (SI). The hour is not, though it is accepted for use with the SI.Since a watt equals one joule per second and because one hour equals 3600 seconds, one watt-hour per kilogram can be expressed in SI units as 3600 joules per kilogram.
633 kJ/kg C/1 to 2.75 V 176 W/kg C/1 20 °C 655 kJ/kg C/1 to 2.75 V 182 W/kg C/1 20 °C 641 kJ/kg 2C to 2.75 V 356 W/kg 2C Electric Fuel Battery Corp. UUV 120 Ah zinc–air fuel cell [71] 630 kJ/kg 500 W/kg C/1 Sion Power 2.5 Ah lithium–sulfur battery [72] 2.15 V 25 °C 1260 kJ/kg 70 W/kg C/5 1209 kJ/kg 672 W/kg 2C
A heat rate value of 2 kWh/kWh gives an efficiency factor of 50%. A heat rate value of 4 MJ/MJ gives an efficiency factor of 25%. For other units, make sure to use a corresponding conversion factor for the units. For example, if using Btu/kWh, use a conversion factor of 3,412 Btu per kWh to calculate the efficiency factor.
The specific heat capacities of iron, granite, and hydrogen gas are about 449 J⋅kg −1 ⋅K −1, 790 J⋅kg −1 ⋅K −1, and 14300 J⋅kg −1 ⋅K −1, respectively. [4] While the substance is undergoing a phase transition , such as melting or boiling, its specific heat capacity is technically undefined, because the heat goes into ...
Energy; system unit code (alternative) symbol or abbrev. notes sample default conversion combinations SI: yottajoule: YJ YJ 1.0 YJ (2.8 × 10 17 kWh) zettajoule: ZJ ZJ 1.0 ZJ (2.8 × 10 14 kWh)
For a water electrolysis unit operating at a constant temperature of 25 °C without the input of any additional heat energy, electrical energy would have to be supplied at a rate equivalent of the enthalpy (heat) of reaction or 285.830 kJ (0.07940 kWh) per gram mol of water consumed. [6] It would operate at a cell voltage of 1.48 V.