Search results
Results From The WOW.Com Content Network
(search substring string) Common Lisp: returns NIL (string-index substring string) ISLISP: returns nil: List.findIndex (List.isPrefixOf substring) (List.tails string) Haskell (returns only index) returns Nothing Str.search_forward (Str.regexp_string substring) string 0: OCaml: raises Not_found
If the tree is traversed from the bottom up with a bit vector telling which strings are seen below each node, the k-common substring problem can be solved in () time. If the suffix tree is prepared for constant time lowest common ancestor retrieval, it can be solved in () time. [2]
After computing E(i, j) for all i and j, we can easily find a solution to the original problem: it is the substring for which E(m, j) is minimal (m being the length of the pattern P.) Computing E ( m , j ) is very similar to computing the edit distance between two strings.
The string spelled by the edges from the root to such a node is a longest repeated substring. The problem of finding the longest substring with at least k {\displaystyle k} occurrences can be solved by first preprocessing the tree to count the number of leaf descendants for each internal node, and then finding the deepest node with at least k ...
Naively computing the hash value for the substring s[i+1..i+m] requires O(m) time because each character is examined. Since the hash computation is done on each loop, the algorithm with a naive hash computation requires O(mn) time, the same complexity as a straightforward string matching algorithm. For speed, the hash must be computed in ...
A description of Manacher’s algorithm for finding the longest palindromic substring in linear time. Akalin, Fred (2007-11-28), Finding the longest palindromic substring in linear time. An explanation and Python implementation of Manacher's linear-time algorithm. Jeuring, Johan (2007–2010), Palindromes. Haskell implementation of Jeuring's ...
A simple and inefficient way to see where one string occurs inside another is to check at each index, one by one. First, we see if there is a copy of the needle starting at the first character of the haystack; if not, we look to see if there's a copy of the needle starting at the second character of the haystack, and so forth.
A string is a substring (or factor) [1] of a string if there exists two strings and such that =.In particular, the empty string is a substring of every string. Example: The string = ana is equal to substrings (and subsequences) of = banana at two different offsets: