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  2. Word problem (mathematics education) - Wikipedia

    en.wikipedia.org/wiki/Word_problem_(mathematics...

    Word problem from the Līlāvatī (12th century), with its English translation and solution. In science education, a word problem is a mathematical exercise (such as in a textbook, worksheet, or exam) where significant background information on the problem is presented in ordinary language rather than in mathematical notation.

  3. Division (mathematics) - Wikipedia

    en.wikipedia.org/wiki/Division_(mathematics)

    If the divisor has a fractional part, one can restate the problem by moving the decimal to the right in both numbers until the divisor has no fraction, which can make the problem easier to solve (e.g., 10/2.5 = 100/25 = 4). Division can be calculated with an abacus. [14]

  4. Word problem (mathematics) - Wikipedia

    en.wikipedia.org/wiki/Word_problem_(mathematics)

    The word problem for an algebra is then to determine, given two expressions (words) involving the generators and operations, whether they represent the same element of the algebra modulo the identities. The word problems for groups and semigroups can be phrased as word problems for algebras. [1]

  5. Fraction - Wikipedia

    en.wikipedia.org/wiki/Fraction

    A simple fraction (also known as a common fraction or vulgar fraction, where vulgar is Latin for "common") is a rational number written as a/b or ⁠ ⁠, where a and b are both integers. [9] As with other fractions, the denominator (b) cannot be zero. Examples include ⁠ 1 / 2 ⁠, − ⁠ 8 / 5 ⁠, ⁠ −8 / 5 ⁠, and ⁠ 8 / −5 ⁠

  6. Division by zero - Wikipedia

    en.wikipedia.org/wiki/Division_by_zero

    However, in other rings, division by nonzero elements may also pose problems. For example, the ring Z /6 Z of integers mod 6. The meaning of the expression 2 2 {\textstyle {\frac {2}{2}}} should be the solution x of the equation 2 x = 2 {\displaystyle 2x=2} .

  7. Singapore math - Wikipedia

    en.wikipedia.org/wiki/Singapore_math

    The solution to this problem could be solved by drawing one bar and dividing it into two parts, with the longer part as 70 and the shorter part as 30. By visualizing these two parts, students would simply solve the above word problem by adding both parts together to build a whole bar of 100.