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The Zebra Puzzle is a well-known logic puzzle.Many versions of the puzzle exist, including a version published in Life International magazine on December 17, 1962. The March 25, 1963, issue of Life contained the solution and the names of several hundred successful solvers from around the world.
Induction puzzles are logic puzzles, which are examples of multi-agent reasoning, where the solution evolves along with the principle of induction. [1] [2]A puzzle's scenario always involves multiple players with the same reasoning capability, who go through the same reasoning steps.
The most elegant form of the answer involves the binary representation of size n: () can be obtained by a one-bit left cyclic shift of n itself. If n is represented in binary as n = 1 b 1 b 2 b 3 … b m {\displaystyle n=1b_{1}b_{2}b_{3}\dots b_{m}} , then the solution is given by f ( n ) = b 1 b 2 b 3 … b m 1 {\displaystyle f(n)=b_{1}b_{2}b ...
In A simple solution to the hardest logic puzzle ever, [6] B. Rabern and L. Rabern offer a variant of the puzzle: a god, confronted with a paradox, will say neither ja nor da and instead not answer at all. For example, if the question "Are you going to answer this question with the word that means no in your language?" is put to True, he cannot ...
There is no rose on the 2, 4, or 6 faces, so these count as zero. There are no petals on the 1 face, so it also counts as zero. There are two petals and four petals on the 3 and 5 faces, respectively. The solution to a given throw is the total number of petals. For example, in a roll of , the only petals are on the 3 and 5 faces, for a total of ...
The bridge and torch problem (also known as The Midnight Train [1] and Dangerous crossing [2]) is a logic puzzle that deals with four people, a bridge and a torch. It is in the category of river crossing puzzles , where a number of objects must move across a river, with some constraints.
It is now clear that if the warden answers B to A ( 1 / 2 of all cases), then 1 / 3 of the time C is pardoned and A will still be executed (case 4), and only 1 / 6 of the time A is pardoned (case 1). Hence C's chances are ( 1 / 3 )/( 1 / 2 ) = 2 / 3 and A's are ( 1 / 6 )/( 1 / 2 ) = 1 / ...
The printed card of the puzzle shows two donkeys, the central part of which has been left blank on purpose. The third part of the card are the riders, and the objective of the puzzle is to arrange the three pieces (the two donkeys and the riders) so the riders are mounted on the donkeys' backs.