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Tables of logarithms prepared by John Napier in 1614 and 1619 used the period (full stop) as the decimal separator, which was then adopted by Henry Briggs in his influential 17th century work. In France, the full stop was already in use in printing to make Roman numerals more readable, so the comma was chosen. [14]
So too are the thousands, with the number of thousands followed by the word "thousand". The number one thousand may be written 1 000 or 1000 or 1,000; larger numbers are written for example 10 000 or 10,000 for ease of reading. European languages that use the comma as a decimal separator may correspondingly use the period as a thousands separator.
Here, the numbers may come as close as they like to 12, including 11.999 and so forth (with any finite number of 9s), but 12.0 is not included. In some European countries, the notation [ 5 , 12 [ {\displaystyle [5,12[} is also used for this, and wherever comma is used as decimal separator , semicolon might be used as a separator to avoid ...
Use a period/full point (.) as the decimal separator, never a comma: 6.57, not 6,57. Numbers between −1 and +1 require a leading zero (0.02, not .02); exceptions are sporting performance averages (.430 batting average) and conventional terms such as .22 caliber.
Punctuation in the English language helps the reader to understand a sentence through visual means other than just the letters of the alphabet. [1] English punctuation has two complementary aspects: phonological punctuation, linked to how the sentence can be read aloud, particularly to pausing; [2] and grammatical punctuation, linked to the structure of the sentence. [3]
The comma-free approach is often used with partial quotations: The report observed "a 45% reduction in transmission rate". A comma is required when it would be present in the same construction if none of the material were a quotation: In Margaret Mead's view, "we must recognize the whole gamut of human potentialities" to enrich our culture.
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Conversely the period of the repeating decimal of a fraction c / d will be (at most) the smallest number n such that 10 n − 1 is divisible by d. For example, the fraction 2 / 7 has d = 7, and the smallest k that makes 10 k − 1 divisible by 7 is k = 6, because 999999 = 7 × 142857. The period of the fraction 2 / 7 is ...